Subset Sum/ Combination sum2 solution not working for larger numbers?

Question

I'm trying to use subset sum/combination sum 2 solution to solve a problem.

Currently, it works for smaller numbers and certain numbers in my list. But it doesnt work for all. In fact, when I put up larger numbers, the output I get is an empty list. I was wondering if any of you had a smiliar problem and a possible solution.

To give you an idea, with the code I currently have, if the input is the following:

trial_list = [1.5,2.5,3.7,4,4.3,5,5,5,3,10]
trial_list_target = 20.5

combinationSum2(trial_list, trial_list_target)

the output that I currently get is

[[1.5, 4, 5, 5, 5],
 [1.5, 4, 5, 10],
 [2.5, 3, 5, 5, 5],
 [2.5, 3, 5, 10],
 [2.5, 3.7, 4.3, 5, 5],
 [2.5, 3.7, 4.3, 10]]

which is correct

And if I use this as an input:

trial_list2 = [10,15,20,20,25,30,15,87,10,7,100]
trial_list2_target = 107

combinationSum2(trial_list2, trial_list2_target)

The output is:

[[7, 10, 10, 15, 15, 20, 30],
 [7, 10, 10, 15, 20, 20, 25],
 [7, 10, 15, 20, 25, 30],
 [7, 15, 15, 20, 20, 30],
 [7, 100],
 [10, 10, 87],
 [20, 87]]

Again which is correct.

However, if I have the following list and target as an input:

trial_list3 = [806.0, 687.67, 590.9, 587.71, 561.88, 493.73, 427.16, 427.16, 412.04, 272.2, 262.82, 262.82, 86.15, 86.15, 86.15, 86.15, 86.15, 86.15, 3.0]

trial_list3_target = 959.87

combinationSum2(trial_list3, trial_list3_target)

The output I get is:

[]

Thats literally my output when it should be

[687.67,272.2].

please help, I'm literally struggling to get why this is happening

FYI, the argument for my function is passed through a pandas dataframe column. Thats the list I'm using as an argument.

This is the whole code I am using:

def combinationSum2(candidates, target):
    # Sorting in earlier cell didnt work so sort here
    candidates.sort()                      
    result = []
    combine_sum_2(candidates, 0, [], result, target)
    return result
    
def combine_sum_2(nums, start, path, result, target):
    # if sum greater than path, stop working
    if not target:
        result.append(path)
        return
    
    for i in range(start, len(nums)):
        # Not sure what this does, copy paste stack overslow
        if i > start and nums[i] == nums[i - 1]:
            continue

        # I think this is to limit search. i.e, if number > target then stop working
        if nums[i] > target:
            break

        # We change the start to `i + 1` because one element only could
        # be used once
        combine_sum_2(nums, i + 1, path + [nums[i]], 
                           result, target - nums[i])