'Stopping a CSS animation but letting its current iteration finish
I have the following HTML:
<div class="rotate"></div>
And the following CSS:
@-webkit-keyframes rotate {
to {
-webkit-transform: rotate(360deg);
}
}
.rotate {
width: 100px;
height: 100px;
background: red;
-webkit-animation-name: rotate;
-webkit-animation-duration: 5s;
-webkit-animation-iteration-count: infinite;
-webkit-animation-timing-function: linear;
}
I want to know if there is a way (using JavaScript) to stop the animation but let it finish its current iteration (preferably by changing one or a few CSS properties). I have tried setting -webkit-animation-name to have a blank value but that causes the element to jump back to its original position in a jarring fashion. I have also tried setting -webkit-animation-iteration-count to 1 but that does the same thing.
Solution 1:[1]
Stop the animation upon receiving an animationiteration event. Something like this (using jQuery):
CSS
@-webkit-keyframes rotate {
to {
-webkit-transform: rotate(360deg);
}
}
.rotate {
width: 100px;
height: 100px;
background: red;
}
.rotate.anim {
-webkit-animation-name: rotate;
-webkit-animation-duration: 5s;
-webkit-animation-iteration-count: infinite;
-webkit-animation-timing-function: linear;
}
HTML
<div class="rotate anim">TEST</div>
<input id="stop" type="submit" value="stop it" />
JS (JQuery)
$("#stop").click(function() {
$(".rotate").one('animationiteration webkitAnimationIteration', function() {
this.classList.remove("anim");
});
});
Fiddle: http://jsfiddle.net/jmp2fakn/
Note that I'm using .one here (not .on) so that the handler only runs once. That way, the animation can later be restarted.
Solution 2:[2]
Do you mean you want the animation to stop where it is when it ends without jumping back to its original position?
Then you want:
Animate something moving from one place to another and have it stay there: animation-fill-mode:forwards;
check this link:
http://www.w3schools.com/cssref/css3_pr_animation-fill-mode.asp
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | |
| Solution 2 | user3374200 |
