'SQL Timeline Query
read already some post but was not able to find a solution yet.
I gota table which looks like this:
and I would like to transform this data, so that I got a line (or row) per ID and an entry per date which displays the Status. The value column does not change its value for the corresponding id.
or
I am currently not able to do it. Even without the value row/line.
CREATE TABLE test (
id INT,
date1 text,
status1 INT,
value1 INT
);
INSERT INTO test VALUES (1, '01.01.2022', 1, 60);
INSERT INTO test VALUES (2, '01.01.2022', 1, 30);
INSERT INTO test VALUES (3, '01.01.2022', 7, 90);
INSERT INTO test VALUES (1, '02.01.2022', 7, 60);
INSERT INTO test VALUES (2, '02.01.2022', 7, 30);
INSERT INTO test VALUES (3, '02.01.2022', 3, 90);
INSERT INTO test VALUES (1, '03.01.2022', 7, 60);
INSERT INTO test VALUES (2, '03.01.2022', 5, 30);
INSERT INTO test VALUES (3, '03.01.2022', 7, 90);
Based on your suggestions I tried:
SELECT *
FROM
(
SELECT id, value1
FROM test
) AS SourceTable
PIVOT(AVG(status1) FOR date1 IN(select DISTINCT date1
from test)) AS PivotTable;
But I can not find my error.
Solution 1:[1]
Schema (MySQL v8.0)
CREATE TABLE test (
id INT,
date text,
status INT,
value INT
);
INSERT INTO test VALUES (1, '01.01.2022', 1, 60);
INSERT INTO test VALUES (2, '01.01.2022', 1, 30);
INSERT INTO test VALUES (3, '01.01.2022', 7, 90);
INSERT INTO test VALUES (1, '02.01.2022', 7, 60);
INSERT INTO test VALUES (2, '02.01.2022', 7, 30);
INSERT INTO test VALUES (3, '02.01.2022', 3, 90);
INSERT INTO test VALUES (1, '03.01.2022', 7, 60);
INSERT INTO test VALUES (2, '03.01.2022', 5, 30);
INSERT INTO test VALUES (3, '03.01.2022', 7, 90);
Query #1
SELECT
ID,
MAX(VALUE) AS VALUE,
sum(CASE WHEN date = '01.01.2022' THEN status ELSE 0 END) AS '01.01.2022',
sum(CASE WHEN date = '02.01.2022' THEN status ELSE 0 END) AS '02.01.2022',
sum(CASE WHEN date = '03.01.2022' THEN status ELSE 0 END) AS '03.01.2022'
FROM test
GROUP BY ID;
| ID | VALUE | 01.01.2022 | 02.01.2022 | 03.01.2022 |
|---|---|---|---|---|
| 1 | 60 | 1 | 7 | 7 |
| 2 | 30 | 1 | 7 | 5 |
| 3 | 90 | 7 | 3 | 7 |
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | YuTing |



