'SQL Server: GROUP BY with multiple columns produces duplicate results
I'm trying to include a 3rd column into my existing SQL Server query but I am getting duplicate result values.
Here is an example of the data contained in tb_IssuedPermits:
| EmployeeName | Current |
|--------------|---------|
| Person A | 0 |
| Person A | 0 |
| Person B | 1 |
| Person C | 0 |
| Person B | 0 |
| Person A | 1 |
This is my current query which produces duplicate values based on 1 or 0 bit values.
SELECT EmployeeName, COUNT(*) AS Count, [Current]
FROM tb_IssuedPermits
GROUP BY EmployeeName, [Current]
| EmployeeName | Count | Current |
|--------------|-------|---------|
| Person A | 2 | 0 |
| Person B | 1 | 0 |
| Person C | 1 | 0 |
| Person A | 1 | 1 |
| Person B | 1 | 1 |
Any ideas on how I can amend my query to have the following expected result? I want one result row per EmployeeName. And Current shall be 1, if for the EmployeeName exists a row with Current = 1, else it shall be 0.
| EmployeeName | Count | Current |
|--------------|-------|---------|
| Person A | 3 | 1 |
| Person B | 2 | 1 |
| Person C | 1 | 0 |
The result does not need to be in any specific order.
TIA
Solution 1:[1]
If your Current column contains the string values 'FALSE' and 'TRUE' you can do this
SELECT EmployeeName, Count(*) AS Count,
MAX([Current]) AS Current
FROM tb_IssuedPermits
GROUP BY EmployeeName
It's a hack but it works: MAX will get the TRUE from each group if there is one.
If your Current column is a BIT, cast to INT and cast back, as @ThorstenKettner suggested.
SELECT EmployeeName,
Count(*) AS Count,
CAST(MAX(CAST([Current] AS INT)) AS BIT) AS Current
FROM tb_IssuedPermits
GROUP BY EmployeeName
Alternatively, you can use conditional aggregation:
SELECT EmployeeName,
Count(*) AS Count,
CAST(COUNT(NULLIF(Current, 0)) AS BIT) AS Current
FROM tb_IssuedPermits
GROUP BY EmployeeName
Solution 2:[2]
you can do like this
SELECT EmployeeName, Count(1) AS Count,SUM(CAST([Current]AS INT)) AS Current FROM tb_IssuedPermits GROUP BY EmployeeName
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | |
| Solution 2 | Suraj S. |
