'Sorry I need to hide
Elon Reeve Musk FRS is an entrepreneur and business magnate. He is the founder, CEO, and Chief Engineer at SpaceX; early-stage investor, CEO, and Product Architect of Tesla, Inc.; founder of The Boring Company; and co-founder of Neuralink and OpenAI.
Solution 1:[1]
Your inner select returns a table. That can't be used as parameter to match a WHERE IN condition. Instead try using an INNER JOIN
sum(decode(
select sum(dou.noukn)
from dou
join v_kzeiritsu on
dou.zeiritsu = v_kzeiritsu.zeiritsu
)) as noukn2;
Solution 2:[2]
Just move your sum logic inside select as follows:
(SELECT SUM(DOU$2.NOUKN)
FROM SDNISHI.V_KZEIRITSU V
WHERE DOU$2.ZEIRITSU = V.ZEIRITSU) AS NOUKN2
In case If it gives aggregation error then use sum(above query) AS NOUKN2
Solution 3:[3]
Your code is very strange. For instance, it seems to assume that V_KZEIRITSU has one row. But, you can move this to the FROM clause:
SELECT SUM(CASE WHEN DOU.ZEIRITSU = K.ZEIRITSU THEN DOU.NOUKN ELSE 0 END) AS NOUKN2
FROM DOU LEFT JOIN
V_KZEIRITSU K
ON 1=1 -- in case the table is really empty
A slightly more reasonable version would be:
SELECT SUM(DOU.NOUKN) AS NOUKN2
FROM DOU LEFT JOIN
V_KZEIRITSU K
ON DOU.ZEIRITSU = K.ZEIRITSU -- in case the table is really empty
It seems rather unlikely to me that this is what you really intend. If not, I would suggest that you ask a new question with appropriate same data, desired results, and explanation of the results. A non-working query should not be expected to provide the same level of information.
Solution 4:[4]
I'd say that it is, actually, as simple as
select sum(dou.noukn)
from dou
where dou.zeiritsu in (select zeiritsu from v_kzeiritsu)
(I'm not sure what dou is (table? alias?), but I hope you do.)
After you edited the question, I'm editing the answer. I marked with "--> this" two lines that - in my opinion - might help. As previously, the whole sum(case ...) as noukn2 is replaced by a simple sum(dou$2.noukn).
Note that - in Oracle - you can't use as keyword for table alias. For example:
- no:
from employees as e - yes:
from employees e
Here's your query:
SELECT DOU$2.CUSTCD AS CUSTCD,
DOU$2.CHUNO AS CHUNO,
DOU$2.LINNO AS LINNO,
DOU$2.SHIPDAYYM AS SHIPDAYYM,
SUM (DOU$2.NOUKN) AS NOUKN,
SUM (DOU$2.ZEIKN) AS ZEIKN,
SUM (dou$2.noukn) AS noukn2 --> this
FROM SDNISHI.T_HCHUMON_DOUSOU DOU$2
INNER JOIN SDNISHI.SY_KANRI KNR ON KNR.SHIPDAYYM = DOU$2.SHIPDAYYM
INNER JOIN SDNISHI.T_HCHUMON_MEI MEI
ON MEI.CUSTCD = DOU$2.CUSTCD
AND MEI.CHUNO = DOU$2.CHUNO
AND MEI.LINNO = DOU$2.LINNO
AND MEI.SHIPDAYYM = DOU$2.SHIPDAYYM
AND MEI.USEDNGKBN = '0'
AND MEI.CANCELKBN = '0'
LEFT OUTER JOIN SDNISHI.T_HCHUMON_HD HD
ON HD.CUSTCD = MEI.CUSTCD
AND HD.CHUNO = MEI.CHUNO
AND HD.LINNO = MEI.LINNO
AND HD.USEDNGKBN = '0'
AND HD.CANCELKBN = '0'
AND isnull (HD.CANKBN, '00') = '00'
JOIN v_keziritsu vk ON vk.zeiritsu = dou$2.zeiritsu --> this
WHERE DOU$2.USEDNGKBN = '0'
AND DOU$2.CANCELKBN = '0'
AND ( ( MEI.CHGDELKBN = '1'
AND MEI.HDOUSOUKBN = '02'
AND ( MEI.CHUSU > 0
OR MEI.BCHUSU > 0))
OR ( MEI.CHGDELKBN != '1'
AND HD.HDOUSOUKBN = '02'
AND ( MEI.CHKBTNFGA = '1'
AND HD.CHUSU > 0)
OR ( MEI.CHKBTNFGB = '1'
AND HD.BCHUSU > 0)))
GROUP BY DOU$2.CUSTCD,
DOU$2.CHUNO,
DOU$2.LINNO,
DOU$2.SHIPDAYYM
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | procra |
| Solution 2 | Popeye |
| Solution 3 | Gordon Linoff |
| Solution 4 |
