'sinon: How to stub an entire class, rather than just a method
I have a class under test that creates instances of another class. I want to stub out the entirety of the second class, so that its constructor never gets called. For example, If I have this setup:
Test.js
class Test {
constructor() {
}
func() {
let foo = new Foo()
foo.hello()
}
}
Foo.js
class Foo {
constructor() {
this.a = 1
this.b = 2
this.c = 3
console.log('original constructor')
}
hello() {
console.log('original hello')
}
goodbye() {
console.log('original goodbye')
}
}
In my test file, I want to somehow stub out the entirety of the Foo class, so that when I run my test for for Test.func() it doesn't call the original Foo constructor, but rather a stubbed constructor that returns an fake Foo object. I'll then stub the hello function of the fake Foo object to print stubbed hello instead of original hello.
How can I stub the entire class like this?
NOTE: I do NOT want to create a stub instance that I can use inside my test file. I need to stub the constructor itself, so that if something up the stack calls the constructor, it gets back a stub instance.
Solution 1:[1]
In sinon documentation:
If you want to create a stub object of MyConstructor, but don’t want the constructor to be invoked, use this utility function.
var stub = sinon.createStubInstance(MyConstructor)
Solution 2:[2]
// A.spec.js
import { A } from './A';
import * as BClass from './B';
describe('A Test', () => {
beforeEach(() => {
class MockB { // The fake B
constructor(params) { /* do some things */ }
introduce() { /* return a stub */ }
locate() { /* do some things and return a stub */ }
}
sinon.stub(BClass, 'B').callsFake((args) => {
return new MockB(args);
}
}
it('should assert personhood', () => { /* bla bla */ }
});
The below link helped me a lot.
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | rad |
| Solution 2 | Debasis Mondal |
