'Show only country_id =1 in list (Symfony + Sonata)
This is my simple listing of the "News" entity
protected function configureListFields(ListMapper $list): void
{
$list
->filte
->add('id')
->add('name')
->add('description')
->add('createdAt')
->add('updatedAt')
->add(ListMapper::NAME_ACTIONS, null, [
'actions' => [
'show' => [],
'edit' => [],
'delete' => []
],
]);
}
The News entity also has a country_id field (I won't show). I need show only the news with country_id = 1. How?
Solution 1:[1]
Ok, I solved with documentation
protected function configureQuery(ProxyQueryInterface $query): ProxyQueryInterface
{
$query = parent::configureQuery($query);
$rootAlias = current($query->getRootAliases());
$query->andWhere(
$query->expr()->eq($rootAlias . '.my_field', ':my_param')
);
$query->setParameter('my_param', 'my_value');
return $query;
}
But need made several changes beacuse $query not is a QueryBuilder Object.
protected function configureQuery(ProxyQueryInterface $query): ProxyQueryInterface
{
$query = parent::configureQuery($query);
$query_qb = $query->getQueryBuilder();
$rootAlias = current($query->getQueryBuilder()->getRootAliases());
$query_qb->andWhere(
$query_qb->expr()->eq($rootAlias . '.idCountry', ':idCountry')
);
$query_qb->setParameter('idCountry', $this->security->getUser()->getCountry()->getId());
return $query;
}
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Leonardo |
