separating out numbers in Reg_exp (Oracle)

Question

I have tried different variations on this query to no avail. To give context the numbers below are examples for contractions during labor. I am looking to parse out the first number and the 2nd if available- What I have so far below-I have it posted in the comments what I do & do not want. Essentially ID 1-3 parsed into separate numbers First number in ID 4 & 5-

Thank you in advance

with test as
(select 1 as ID,'2-4' as MEAS_VALUE from dual union all --want 2 & 4
 select 2 as ID,'2.5-4' as MEAS_VALUE from dual union all --want 2.5  & 4
 select 3 as ID,'2-4.5' as MEAS_VALUE from dual union all --want 2 & 4.5
 select 4 as ID,'x2' as MEAS_VALUE from dual union all --want x2
 select 5 as ID,'2 in 20 minutes' as MEAS_VALUE from dual) --want 2 but not  20
 select test.*,
REGEXP_SUBSTR(MEAS_VALUE,'\d+.?([^-]\d)',1,1) as num1,
REGEXP_SUBSTR(MEAS_VALUE,'\d+',1,2) as num2
from test;

Answer 1

Question says:

I am looking to parse out the first number and the 2nd if available

If so, then:

SQL> with test as
  2  (select 1 as ID,'2-4' as MEAS_VALUE from dual union all --want 2 & 4
  3   select 2 as ID,'2.5-4' as MEAS_VALUE from dual union all --want 2.5  & 4
  4   select 3 as ID,'2-4.5' as MEAS_VALUE from dual union all --want 2 & 4.5
  5   select 4 as ID,'x2' as MEAS_VALUE from dual union all --want x2
  6   select 5 as ID,'2 in 20 minutes' as MEAS_VALUE from dual) --want 2 but not  20
  7  select test.*,
  8    regexp_substr(meas_value, '\d+(\.\d+)?', 1, 1) num1,
  9    regexp_substr(meas_value, '\d+(\.\d+)?', 1, 2) num2
 10  from test;

        ID MEAS_VALUE      NUM1       NUM2
---------- --------------- ---------- ----------
         1 2-4             2          4
         2 2.5-4           2.5        4
         3 2-4.5           2          4.5
         4 x2              2
         5 2 in 20 minutes 2          20

SQL>

There's no rule that explains desired output for IDs 4 (x2; why x? It is not a digit) and 5 (no 20; why not? It is the 2nd digit here).