'Rust Read CSV without header
How does one read a CSV without a header in Rust? I've searched through the docs and gone through like 15 examples each of which is subtly not what I'm looking for.
Consider how easy Python makes it:
csv.DictReader(f, fieldnames=['city'])
How do you do this in Rust?
Current attempt:
use std::fs::File;
use serde::Deserialize;
#[derive(Debug, Deserialize)]
struct CityRow {
city: &str,
pop: u32,
}
fn doit() -> zip::result::ZipResult<()>
{
let filename = "cities.csv";
let mut zip = zip::ZipArchive::new(File::open(filename).unwrap())?;
let mut file = zip.by_index(0).unwrap();
println!("Filename: {}", file.name());
let mut reader = csv::Reader::from_reader(Box::new(file));
reader.set_headers(csv::StringRecord([ "city", "pop" ]));
for record in reader.records() {
// let record: CityRow = record.unwrap();
// let record = record?;
println!("{:?}", record);
}
Ok(())
}
Solution 1:[1]
Use a ReaderBuilder, and call ReaderBuilder::has_headers to disable header parsing. You can then use StringRecord::deserialize to extract and print each record, skipping the first header row:
let mut reader = csv::ReaderBuilder::new()
.has_headers(false)
.from_reader(Box::new(file));
let headers = csv::StringRecord::from(vec!["city", "pop"]);
for record in reader.records().skip(1) {
let record: CityRow = record.unwrap().deserialize(Some(&headers)).unwrap();
println!("{:?}", record);
}
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Smitop |
