'Replace the first 2 lines containing a string with a specific line with a bash script

I need to replace the first 2 occurrences of:

"<version>*"

with

"<version>$NEW_VERSION</version>"

within an already existing xml file.

Original:

<groupId>my.test.group</groupId>
<artifactId>maven-parent</artifactId>
<version>1.3.0-SNAPSHOT</version>
<version>1.3.0-SNAPSHOT</version>

Desired result:

<groupId>my.test.group</groupId>
<artifactId>maven-parent</artifactId>
<version>1.3.1-SNAPSHOT</version>
<version>1.3.1-SNAPSHOT</version>

I've tried for a while now and this:

sed -i -e '0,/<version>*/s/<version>*/<version>1.3.1-SNAPSHOT<\/version>/' pom.xml

gets close, but the resulting string is:

<groupId>my.test.group</groupId>
<artifactId>maven-parent</artifactId>
<version>1.3.1-SNAPSHOT</version>1.3.0-SNAPSHOT</version>
linuxbashawksed


Solution 1:[1]

This might work for you (GNU sed):

sed -E '/<version>/{x;s/^/x/;/xx{2}/!{x;s/(<version>)[^<]*/\1NEW VERSION/;x};x}' file

Match <version> on any line,swap to the hold space, increment a counter and if that counter exceeds the required number of overall substitutions, continue with no further processing.

Otherwise, swap back to the pattern space and substitute the new version.

Sources

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Source: Stack Overflow

Solution Source
Solution 1 potong

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