Removing sequential repeating items from List in Kotlin?

Question

I'm looking for a way in Kotlin to prevent repeating items in a list but still preserve the order. For example

  val list = listOf(ObjectMock(1,"a"), ObjectMock(2,"c"), ObjectMock(3,"c"),
        ObjectMock(4,"a"), ObjectMock(4,"c"), ObjectMock(4,"c"), ObjectMock(1,"a")
        , ObjectMock(1,"c"), ObjectMock(2,"c"), ObjectMock(3,"c"), ObjectMock(4,"a")
        , ObjectMock(2,"b") )

should become

result = listOf(ObjectMock(1,"a"), ObjectMock(2,"c"), ObjectMock(3,"c"),
            ObjectMock(4,"a"), ObjectMock(1,"a") , ObjectMock(2,"c"), ObjectMock(3,"c"), ObjectMock(4,"a")
            , ObjectMock(2,"b") )

I'm using a for loop and check next item then add it to different list but Is there a more elegant way to do this?

Answer 1

this is another way to do it

val list = listOf(1, 2, 3, 4, 4, 4, 1, 1, 2, 3, 4, 4 )
val result = list.fold(emptyList<Int>()){acc, i ->
    if (acc.lastOrNull() != i) acc + i else acc
}

Answer 2

You can do it by using Kotlin Flows

viewModelScope.launch {
        list.asFlow()
            .distinctUntilChanged()
            .collect {
                Log.d(TAG, "distict numbers: $it")
            }
    }