'regular expression capture nth match
Is there any way to, using regular expression, return the nth occurrence? I did search the forums and only found solution that goes beyond regular expression itself (i.e. needs support from the programming language).
Example: Regex:
(?:\$(\d+(?:,\d{3})*\.\d{2}))
Input:
thiscanbeanything$25.74thiscanbesomethingelse
alsowithnewlines$533.63thisonetoo$54.32plusthis$62.42thisneverends
I'd need to extract the first one (which is 25.74). Later on I might need to extract the third one (which is 54.32).
My regex is currently matching all occurrences. I could retrieve the nth element after matches but my question is: is it possible to do it via regular expression only (i.e. the regular expression will return only the nth element I want)?
Thanks!
Solution 1:[1]
for nth match use this pattern (?:.*?\$[0-9.]+){XX}.*?(\$[0-9.]+)
where XX = n-1
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | alpha bravo |
