'Regex matching dates in a string in Javascript
Following up from this thread, im trying to make this work
JavaScript regular expression to match X digits only
string = '2016-2022'
re = /\d{4}/g
result = [...string.matchAll(re)]
This returns an array of two arrays. Is there a way to consolidate this into 1 array?
However it doesn't look like this is returning the desired results
I'm new to regular expression. What am I doing wrong?
Solution 1:[1]
this return an array of matches
result = string.match(re)
Solution 2:[2]
This is a function to parse the string encoding those two year values and return the inner years as items of an array:
let o = parseYearsInterval('2016-2022');
console.log(o);
function parseYearsInterval(encodedValue){
var myregexp = /(\d{4})-(\d{4})/;
var match = myregexp.exec(encodedValue);
if (match != null) {
let d1 = match[1];
let d2 = match[2];
//return `[${d1}, ${d2}]`;
let result = [];
result.push(d1);
result.push(d2);
return result;
} else {
return "not valid input";
}
}
I think there are better ways to do that like splitting the string against the "-" separator and return that value as is like:
console.log ( "2016-2022".split('-') )
Solution 3:[3]
Just do a split if you know that only years are in the string and the strucutre isn't changing:
let arr = str.split("-");
Solution 4:[4]
Question
string = '2016-2022' re = /\d{4}/g result = [...string.matchAll(re)]This returns an array of two arrays. Is there a way to consolidate this into 1 array?
Solution
You may simply flat the result of matchAll.
let string = '2016-2022'
let re = /\d{4}/g
console.log([...string.matchAll(re)].flat())
Alternative
If your structure is given like "yyyy-yyyy-yyyy" you might consider a simple split
console.log('2016-2022'.split('-'))
Solution 5:[5]
var str = '2016-2022';
var result = [];
str.replace(/\d{4}/g, function(match, i, original) {
result.push(match);
return '';
});
console.log(result);
I also wanted to mention, that matchAll does basicly nothing else then an while exec, that's why you get 2 arrays, you can do it by yourself in a while loop and just save back what you need
var result = [];
var matches;
var regexp = /\d{4}/g;
while (matches = regexp.exec('2016-2022')) result.push(matches[0]);
console.log(result);
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Simone Celia |
| Solution 2 | Diego De Vita |
| Solution 3 | John_H_Smith |
| Solution 4 | Lain |
| Solution 5 |
