'React Popper. How to move element relatively parent?

I'm trying to move Popper that is inside parent component. How i can do it?

I tried to use offset property in modifiers object. e.g.:

offset: {
  offset: 20,
}

But offset only move Popper in one direction. If placement={'top' || 'bottom'} => it moves right and left, if placement={'right' || 'left'} => it moves top and bottom. 

const Layer = ({
  children,
  align,
  inner = true,
  parent,
  portal,
}) => (
  <Manager>
    <Popper
      placement={align}
      modifiers={{
        inner: {
          enabled: inner,
        },
      }}
      referenceElement={parent}
    >
      {({ ref, style, placement }) => (
        <div
          ref={ref}
          data-placement={placement}
          style={style}
        >
          {console.log(style)}
          {children}
        </div>
      )}
    </Popper>
  </Manager>
)
popper.jsreact-popper


Solution 1:[1]

Just dealt with this: Place MaterialUI Tooltip "on top" of anchor element? (React)

PopperProps={{
  popperOptions: {
    modifiers: {
      flip: { enabled: false },
      offset: {
        enabled: true,
        offset: '20px 20px'
      }
    }
  }
}}

Solution 2:[2]

I solved it like that. Added topOffset and leftOffset props to popper child and used spread syntax. Don't think it is cleanest solution.

const Layer = ({
  children,
  align,
  inner = true,
  parent,
  portal,
  topOffset,
  leftOffset,
}) => (
  <Manager>
    <Popper
      placement={align}
      modifiers={{
        inner: {
          enabled: inner,
        },
      }}
      referenceElement={parent}
    >
      {({ ref, style, placement }) => (
        <div
          ref={ref}
          data-placement={placement}
          style={{
            ...style,
            top: style.top + topOffset,
            left: style.left  + leftOffset,
          }}
        >
          {console.log(style)}
          {children}
        </div>
      )}
    </Popper>
  </Manager>
)

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1 doublejosh
Solution 2 Mario Petrovic

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