Random number between 0 and 1? [duplicate]

Question

I want a random number between 0 and 1, like 0.3452. I used random.randrange(0, 1) but it is always 0 for me. What should I do?

Answer 1

You can use random.uniform

import random
random.uniform(0, 1)

Answer 2

random.random() does exactly that

>>> import random
>>> for i in range(10):
...     print(random.random())
... 
0.908047338626
0.0199900075962
0.904058545833
0.321508119045
0.657086320195
0.714084413092
0.315924955063
0.696965958019
0.93824013683
0.484207425759

If you want really random numbers, and to cover the range [0, 1]:

>>> import os
>>> int.from_bytes(os.urandom(8), byteorder="big") / ((1 << 64) - 1)
0.7409674234050893

Answer 3

I want a random number between 0 and 1, like 0.3452

random.random() is what you are looking for:

From python docs: random.random() Return the next random floating point number in the range [0.0, 1.0).

---

And, btw, Why your try didn't work?:

Your try was: random.randrange(0, 1)

From python docs: random.randrange() Return a randomly selected element from range(start, stop, step). This is equivalent to choice(range(start, stop, step)), but doesn’t actually build a range object.

So, what you are doing here, with random.randrange(a,b) is choosing a random element from range(a,b); in your case, from range(0,1), but, guess what!: the only element in range(0,1), is 0, so, the only element you can choose from range(0,1), is 0; that's why you were always getting 0 back.

Answer 4

you can use use numpy.random module, you can get array of random number in shape of your choice you want

>>> import numpy as np
>>> np.random.random(1)[0]
0.17425892129128229
>>> np.random.random((3,2))
array([[ 0.7978787 ,  0.9784473 ],
       [ 0.49214277,  0.06749958],
       [ 0.12944254,  0.80929816]])
>>> np.random.random((3,1))
array([[ 0.86725993],
       [ 0.36869585],
       [ 0.2601249 ]])
>>> np.random.random((4,1))
array([[ 0.87161403],
       [ 0.41976921],
       [ 0.35714702],
       [ 0.31166808]])
>>> np.random.random_sample()
0.47108547995356098

Answer 5

random.randrange(0,2) this works!

Answer 6

RTM

From the docs for the Python random module:

Functions for integers:

random.randrange(stop)
random.randrange(start, stop[, step])

    Return a randomly selected element from range(start, stop, step).
    This is equivalent to choice(range(start, stop, step)), but doesn’t
    actually build a range object.

That explains why it only gives you 0, doesn't it. range(0,1) is [0]. It is choosing from a list consisting of only that value.

Also from those docs:

random.random()    
    Return the next random floating point number in the range [0.0, 1.0).

But if your inclusion of the numpy tag is intentional, you can generate many random floats in that range with one call using a np.random function.