'"Too many characters in character literal error"

I'm struggling with a piece of code and getting the error:

Too many characters in character literal error

Using C# and switch statement to iterate through a string buffer and reading tokens, but getting the error in this line:

case '&&':

case '||':

case '==':

How can I keep the == and && as a char?

c++sharpchar


Solution 1:[1]

This is because, in C#, single quotes ('') denote (or encapsulate) a single character, whereas double quotes ("") are used for a string of characters. For example:

var myChar = '=';

var myString = "==";

Solution 2:[2]

Here's an example: 

char myChar = '|';
string myString = "||";

Chars are delimited by single quotes, and strings by double quotes.

The good news is C# switch statements work with strings!

switch (mytoken)
{
    case "==":
        //Something here.
        break;
    default:
        //Handle when no token is found.
        break;
}

Solution 3:[3]

You cannot treat == or || as chars, since they are not chars, but a sequence of chars.

You could make your switch...case work on strings instead.

Solution 4:[4]

A char can hold a single character only, a character literal is a single character in single quote, i.e. '&' - if you have more characters than one you want to use a string, for that you have to use double quotes:

case "&&":

Solution 5:[5]

I believe you can do this using a Unicode encoding, but I doubt this is what you really want.

The == is the unicode value 2A76 so I belive you can do this:

char c = '\u2A76';

I can't test this at the moment but I'd be interested to know if that works for you.

You will need to dig around for the others. Here is a unicode table if you want to look:

http://www.tamasoft.co.jp/en/general-info/unicode.html

Solution 6:[6]

I faced the same issue. String.Replace('\\.','') is not valid statement and throws the same error. Thanks to C# we can use double quotes instead of single quotes and following works String.Replace("\\.","")

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1 Grant Thomas
Solution 2 Only Bolivian Here
Solution 3 driis
Solution 4 BrokenGlass
Solution 5 Abe Miessler
Solution 6

Related Questions