'QSqlDatabasePrivate::removeDatabase: connection 'myConnectionName' is still in use, all queries will cease to work
I have a folder where i have a many databases. Some times may be deleted or added database to the folder. So I use QTimer and read all databases.
It is a my code:
this->timer = new QTimer(this);
this->timer->setInterval(15000);
connect(this->timer, &QTimer::timeout, this, [=]() {
QString path = "C:\\Users\\User\\Desktop\\DAXI SMS SENDER\\SMSSenderAllBASE";
//QString path = qApp->applicationDirPath() + "\\SMSSenderAllBASE";
QDir recoredDir(path);
QStringList allFiles = recoredDir.entryList(QDir::NoDotAndDotDot | QDir::System | QDir::Hidden | QDir::AllDirs | QDir::Files, QDir::DirsFirst);
for (int i = 0; i < allFiles.size(); i++) {
QString fullPath = path + "\\" + allFiles[i];
QString connectionName = allFiles[i];
connectionName = connectionName.remove(connectionName.size() - 4, 4);
QSqlDatabase db = QSqlDatabase::addDatabase("QIBASE", connectionName);
db.setDatabaseName(fullPath);
db.setHostName("localhost");
db.setPort(3050);
db.setUserName("SYSDBA");
db.setPassword("masterkey");
thrdHelperSendSMS *help = new thrdHelperSendSMS(db, this);
connect(help, &thrdHelperSendSMS::helperFinished, this, [=](QString connectionName){
QSqlDatabase t_db = QSqlDatabase::database(connectionName);
t_db.close();
QSqlDatabase::removeDatabase(connectionName);
delete help;
});
help->run();
}
});
this->timer->start();
Yes I'm sure that the helperFinished signal will happen and this time I will not have any connection with this base.
EDIT: If i remove
thrdHelperSendSMS *help = new thrdHelperSendSMS(db, this);
connect(help, &thrdHelperSendSMS::helperFinished, this, [=](QString connectionName){
QSqlDatabase t_db = QSqlDatabase::database(connectionName);
t_db.close();
QSqlDatabase::removeDatabase(connectionName);
delete help;
});
help->run();
example:
for (int i = 0; i < allFiles.size(); i++) {
QString fullPath = path + "\\" + allFiles[i];
QString connectionName = allFiles[i];
connectionName = connectionName.remove(connectionName.size() - 4, 4);
QSqlDatabase db = QSqlDatabase::addDatabase("QIBASE", connectionName);
db.setDatabaseName(fullPath);
db.setHostName("localhost");
db.setPort(3050);
db.setUserName("SYSDBA");
db.setPassword("masterkey");
QSqlDatabase::removeDatabase(connectionName);
}
I have the same error.
Solution 1:[1]
@user3606329's answer is right, but I add this possibility:
QSqlDatabase db = QSqlDatabase::database("sales");
{
QSqlQuery query("SELECT NAME, DOB FROM EMPLOYEES", db);
//use query
}
db = QSqlDatabase();
QSqlDatabase::removeDatabase("sales");
Solution 2:[2]
You can use std::swap to force it destruct on demand.
I basically use BOOST_SCOPE_EXIT for cases when want to call a function on scope exit including not expected exit like through an exception throw.
#include <boost/scope_exit.hpp>
{
QSqlDatabase db;
BOOST_SCOPE_EXIT(this_, &db) { // by reference, otherwise it will copy a stack object
// access object here through the this_ instead of this ...
if (db.isOpen()) {
db.close(); // closing if not yet closed before connection remove
}
std::swap(db, QSqlDatabase{}); // destruct via swap
// CAUTION:
// From this point you must not call to `QSqlDatabase::database("MYDB", ...)`, otherwise it will return another constructed object!
//
QSqlDatabase::removeDatabase("MYDB");
} BOOST_SCOPE_EXIT_END
// ui change from here ...
// accomplish last ui changes before long blocking operation
qApp->processEvents();
db = QSqlDatabase::addDatabase("...", "MYDB");
// database access from here ...
}
Solution 3:[3]
QSqlDatabase db = QSqlDatabase::addDatabase("QSQLITE", "conn_name");
db.open();
if (db.open())
{
qDebug()<<"DataBase is Open";
}
else
{
qDebug()<<"DataBase is Not Open";
}
QSqlQueryModel * model = new QSqlQueryModel();
QSqlQuery query(QSqlDatabase::database("conn_name"));
query.exec("SMTHING")
if (query.exec())
{
while (query.next())
{
ui->QTableView->setModel(model);
model->setHeaderData(2, Qt::Horizontal, QObject::tr("????"));
}
}
db.close();
QSqlDatabase::removeDatabase("conn_name");
Here is my code
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Albertino80 |
| Solution 2 | Andry |
| Solution 3 | GKS |
