Python - Run shell command, get stdout and stderr as a variable, but hide from user?

Question

I would like to have my Python script run a Linux shell command and store the output in a variable, without the command's output being shown to the user. I have tried this with os.system, subprocess.check_output, subprocess.run, subprocess.Popen, and os.popen with no luck.

My current method is running os.system("ls -l &> /tmp/test_file") so the command stdout and stderr are piped to /tmp/test_file, and then I have my python code read the file into a variable and then delete it.

Is there a better way of doing this so that I can have the command output sent directly into the variable without having to create and delete a file, but keep it hidden from the user?

Thanks

Answer 1

You can use subprocess.run function.

from subprocess import run

data = run("ANY COMMAND HERE",capture_output=True,shell=True)
print(data.stdout)
print(data.stderr)