'Python Librosa : What is the default frame size used to compute the MFCC features?

Using Librosa library, I generated the MFCC features of audio file 1319 seconds into a matrix 20 X 56829. The 20 here represents the no of MFCC features (Which I can manually adjust it). But I don't know how it segmented the audio length into 56829. What is the frame size it takes process the audio?

import numpy as np
import matplotlib.pyplot as plt
import librosa

def getPathToGroundtruth(episode):
    """Return path to groundtruth file for episode"""
    pathToGroundtruth = "../../../season01/Audio/" \
                        + "Season01.Episode%02d.en.wav" % episode
    return pathToGroundtruth

def getduration(episode):
    pathToAudioFile = getPathToGroundtruth(episode)
    y, sr = librosa.load(pathToAudioFile)
    duration = librosa.get_duration(y=y, sr=sr)
    return duration
def getMFCC(episode):
    filename = getPathToGroundtruth(episode)
    y, sr = librosa.load(filename)  # Y gives 
    data = librosa.feature.mfcc(y=y, sr=sr)
    return data


data = getMFCC(1)
python-3.xaudiomfcc


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