python binding for enable_if_t<is_same_v<U, void>>

Question

I need to bind for a fun of set(), which is defined as below:

template<typename U=T> std::enable_if_t<!is_same_v<U, void>> set(U const& val)
{
   set_value(val);
}

template<bool _Cond, typename _Tp=void>
using enable_if_t = typename enable_if<_Cond, _Tp>::type;

I tried to bind for the return type (std::enable_if_t<>):

void bind_enable_if_t(py::module &m)
{
    py::class<std::enable_if_t<bool, OutputDataType> pyClass(m, "enable_if_t", py::module_local()); 
}

I got error messages:

In function 'void bind_enable_if_t(pybind11:module&)':
error: type/value mismatch at argument 1 in template parameter list for 'template<bool _Cond, class _Tp> using enable_if_t = typename std::enable_if::type'

note: expected a constant of type 'bool', got 'bool'

What is the meaning of "expected a constant of type 'bool', got 'bool''? What'll be the correct way to do the binding?

Thanks for any suggestions.