'Proper way to make various concurrent calls in JS and await them all?

Consider the following:

async makesomething () {
  // These first calls should all be done concurrent...
  call1()
  call2()
  call3()
  // But I want to wait all the previous call to finish before calling call4()
  call4()
}

Adding an await before call1-2() will make the next call wait for it to finish, which is not the desired behavior... And if I add it on call3, call4 might happen before call1-2 finishes which again is not the desired behavior here... So how do I make call4 wait for the previous calls to finish without blocking any of the previous calls?

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'Proper way to make various concurrent calls in JS and await them all?

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