printf returning 6422044 for the value of variable

Question

Question

Basically, I have a simple C code to return the value of a variable, but, if I change the & of the scanf() and the printf the returned value of variables is changed. What is the technical explanation for this event?

(input: 3) printf returning: 3

#include <stdio.h>
#include <stdlib.h>

void main(){
    int x = 1;
    scanf("%d", &x);
    printf("%d", x);
}

(input: 3) printf returning: 6422044

#include <stdio.h>
#include <stdlib.h>

void main(){
    int x = 1;
    scanf("%d", &x);
    printf("%d", &x);
}

(input: 3) printf returning: (nothing)

#include <stdio.h>
#include <stdlib.h>

void main(){
    int x = 1;
    scanf("%d", x);
    printf("%d", &x);
}

Answer 1

On first code it is simple. You are storing the value in the address of x so you are mentioning &x and you can access the value by x.

on second code your are getting the value as i mentioned above. in printf statement you are prinintg the address of x.

Basically & refers to address you will see lot of them while you studying the concept Pointer.

Answer 2

just remove the & from printf("%d", &x); , it will definitely solve your problem.