'Print line numbers from grep separated with a comma

I used grep to get the line numbers from a file where a particular string occurred. What if I want these line numbers to appear in on line separated by a comma not vertically in a line?

cFont=$(grep -icE "<font *" $htmlFile)
if [ $cFont -gt 0 ] ; then
  echo "There are $cFont line(s) with <font> tag, they are: " >> ~/Desktop/errors.txt
  grep -inE "<font *" $htmlFile |cut -f1 -d: >> ~/Desktop/errors.txt
fi

The out put was 

There are 4 line(s) with <font> tag, they are: 
14
43
46
72

I want it to be

There are 4 line(s) with <font> tag, they are: 
14, 43, 46, 72
bashshellgrepcut


Solution 1:[1]

Use:

grep -inE "<font *" $htmlFile |cut -f1 -d:| tr '\n' ','|sed -e "s/,$//" >> ~/Desktop/errors.tr

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1 Juan Diego Godoy Robles

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