print double type data and decimal represention

Question

#include <stdint.h>
#include <stdlib.h>

typedef struct{
uint64_t f: 23;
uint64_t e: 8;
uint64_t s: 8;
} float_struct_t;

typedef union {
float fp;
uint32_t bits;
float_struct_t bitss; 
} float_bits_t;


void printBitsFloat(float_bits_t *);


int main() {
float values[17];// =  {0.0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16};
float_bits_t x1;





x1.bitss.s = 0; 
x1.bitss.e = -2+127; 
x1.bitss.f = 0x4ccccd; //O prefixo 0x indica que o valor é representado em hexadecimal




int valores_e[] = {-2, -1, 0, 1, 2, -2, -3, -6, 1, 4, 5, 7};  
int valores_f[] = {0x0, 0x0, 0x0, 0x0, 0x0, 0x4ccccd, 0x4ccccd, 0x23d70a, 0x0, 0x200000, 
0x200000, 0x480000}; 

for(int i = 0; i<sizeof(values)/sizeof(float); ++i) {
  x1.bitss.s = values[i];
  printf("%.1e: ", x1.fp);
  printBitsFloat(&x1);
  printf(" Sign = %d Exp(decimal) = %3d Fraction = 0x%x=%f", x1.bitss.s, x1.bitss.e-127, x1.bitss.f);
  putchar('\n');
}
 
}

/* Imprime o valor de cada bit, da esquerda para direita, desde o  
 bit firstBit (0 a 63) até ao bit lastBit (0 a 63 e não superior a firstBit)
*/
void printBits64(uint64_t v, int firstBit, int lastBit) {
uint64_t mask = 1; 

if(firstBit < lastBit)
  abort();

if(firstBit>0)
  mask = mask << firstBit;

if(mask & v)
  putchar('1');
else
  putchar('0');

if(firstBit == lastBit)
  return;
else {
  printBits64(v, --firstBit, lastBit);
}
}


void printBitsFloat(float_bits_t *x){
printBits64(x->bits, 31, 31); putchar(' ');
printBits64(x->bits, 30, 23); putchar(' ');
printBits64(x->bits, 22, 0);
}

Hello everyone, I'm trying to make a problem where a certain code is given and ask me to add to the code some additional way to print the decimal representation of the numbers. I used %f but all the results are giving me 0.0000. What could I do wrong? Later I am also asked to add the code that allows me to store and print the double type data, how can I do that? Thank you