'POWER BI - DAX - Measure filter
I have a dax measure . This measure have 1 data . This is "GOOGLE";"YOUTUBE";"AMAZON"
I want to use this 1 line string result in FILTER.
CALCULATE(SUM(_TABLE);_TABLE.COMPANIESNAME; FILTER(_TABLE.COMPANIESNAME IN { mymeasure } ))
Does anyone can help me solve this problem ?
Thank you for help
Solution 1:[1]
There are probably way better ways to do what you want. You are treating Power BI like a relational database when you should be using it like a Star Schema. But without more info, I'm just going to answer the question.
Here's my sample table:
// Table
let
Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WcsxNrMrPU9JRMlSK1YlWcs/PT89JBXKNwNzI/NKQ0iQQ3xjMd0tMTk3Kz88GCpgoxcYCAA==", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [Company = _t, Count = _t]),
#"Changed Type" = Table.TransformColumnTypes(Source,{{"Count", Int64.Type}})
in
#"Changed Type"
I don't have your DAX measure or its name, so I'm using this:
CompanyList = """Google"";""YouTube"";""Amazon"""
Just to prove it's the same as your measure, here it is in the report:

From this post I created a DAX formula that will parse your DAX value into a table with one row for each company name. Add this as a DAX table from Modeling > New Table. I named mine "Filtered table".
Filtered table = VAR CommaSeparatedList = [CompanyList]
VAR BarSeparatedList =
SUBSTITUTE ( CommaSeparatedList, ";", "|" )
VAR Length =
PATHLENGTH ( BarSeparatedList )
VAR Result =
SELECTCOLUMNS (
GENERATESERIES ( 1, Length ),
"Company", SUBSTITUTE( PATHITEM ( BarSeparatedList, [Value] ), """", "")
)
RETURN
Result
Here's what the table looks like:
Add a relationship between the two tables like this (Modeling > Manage relationships > New...):

Then add a DAX column to the filtered table by selecting the table and then Modeling > New Column
Count = CALCULATE(SUM('Table'[Count]))
You can total it up with this DAX measure:
Filtered total = SUM('Filtered table'[Count])
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | TheRizza |





