PHP: using strip_tags with parameters with array_map

Question

I've looked at other posts but can't seem to get to a working solution in place to the point where I am now looking at a blank canvas.

$l = array_map( 'strip_tags', $l );

This is what I currently have but I would like to keep <p>, <a>, <ul> and <li> tags

Answer 1

If $l is an array, First of all, avoid to affect to the variable the output of a function with which you pass the variable itself

you can write something like this:

$output = array_map(function($item) {
    return strip_tags($item, '<p><a><ul><li>');
}, $l)

Answer 2

To add to JessGabriel's answer:

Starting in PHP 8.1, you can't pass NULLs to internal function parameters (https://php.watch/versions/8.1/internal-func-non-nullable-null-deprecation). So for strip_tags, I have a quick and dirty if statement so it doesn't toss an error:

$output= array_map(function($v){ 
        if (is_null($v)) { 
            $v = '';
        }
        return trim(strip_tags($v));
    }, $myArray);