'PHP form - on submit stay on same page

I have a PHP form that is located on file contact.html.

The form is processed from file processForm.php.

When a user fills out the form and clicks on submit, processForm.php sends the email and direct the user to - processForm.php with a message on that page "Success! Your message has been sent."

I do not know much about PHP, but I know that the action that is calling for this is:

// Die with a success message
die("<span class='success'>Success! Your message has been sent.</span>");

How can I keep the message inside the form div without redirecting to the processForm.php page?

I can post the entire processForm.php if needed, but it is long.

phphtmlformssubmit


Solution 1:[1]

In order to stay on the same page on submit you can leave action empty (action="") into the form tag, or leave it out altogether.

For the message, create a variable ($message = "Success! You entered: ".$input;") and then echo the variable at the place in the page where you want the message to appear with <?php echo $message; ?>.

Like this:

<?php
$message = "";
if(isset($_POST['SubmitButton'])){ //check if form was submitted
  $input = $_POST['inputText']; //get input text
  $message = "Success! You entered: ".$input;
}    
?>

<html>
<body>    
<form action="" method="post">
<?php echo $message; ?>
  <input type="text" name="inputText"/>
  <input type="submit" name="SubmitButton"/>
</form>    
</body>
</html>

Solution 2:[2]

The best way to stay on the same page is to post to the same page:

<form method="post" action="<?=$_SERVER['PHP_SELF'];?>">

Solution 3:[3]

There are two ways of doing it:

  1. Submit the form to the same page: Handle the submitted form using PHP script. (This can be done by setting the form action to the current page URL.)

    if(isset($_POST['submit'])) {
    // Enter the code you want to execute after the form has been submitted
    // Display Success or Failure message (if any)
  } else {
    // Display the Form and the Submit Button
}

  2. Using AJAX Form Submission which is a little more difficult for a beginner than method #1.

Solution 4:[4]

You can use the # action in a form action:

<?php
    if(isset($_POST['SubmitButton'])){ // Check if form was submitted

        $input = $_POST['inputText']; // Get input text
        $message = "Success! You entered: " . $input;
    }
?>

<html>
    <body>
        <form action="#" method="post">
            <?php echo $message; ?>
            <input type="text" name="inputText"/>
            <input type="submit" name="SubmitButton"/>
        </form>
    </body>
</html>

Solution 5:[5]

Friend. Use this way, There will be no "Undefined variable message" and it will work fine.

<?php
    if(isset($_POST['SubmitButton'])){
        $price = $_POST["price"];
        $qty = $_POST["qty"];
        $message = $price*$qty;
    }

        ?>

    <!DOCTYPE html>
    <html>
    <head>
        <title></title>
    </head>
    <body>
        <form action="#" method="post">
            <input type="number" name="price"> <br>
            <input type="number" name="qty"><br>
            <input type="submit" name="SubmitButton">
        </form>
        <?php echo "The Answer is" .$message; ?>

    </body>
    </html>

Solution 6:[6]

You have to use code similar to this:

echo "<div id='divwithform'>";

if(isset($_POST['submit']))  // if form was submitted (if you came here with form data)
{
    echo "Success";
}
else                // if form was not submitted (if you came here without form data)
{
    echo "<form> ... </form>";
} 

echo "</div>";

Code with if like this is typical for many pages, however this is very simplified.

Normally, you have to validate some data in first "if" (check if form fields were not empty etc).

Please visit www.thenewboston.org or phpacademy.org. There are very good PHP video tutorials, including forms.

Solution 7:[7]

You can see the following example for the Form action on the same page

<form action="" method="post">
<table border="1px">
    <tr><td>Name: <input type="text" name="user_name" ></td></tr>
    <tr><td align="right"> <input type="submit" value="submit" name="btn"> 
</td></tr>
</table>
</form>

<?php
  if(isset($_POST['btn'])){
     $name=$_POST['user_name'];
     echo 'Welcome '. $name; 
   }
 ?>

Solution 8:[8]

Try this... worked for me

<form action="submit.php" method="post">
<input type="text" name="input">
<input type="submit">
</form>

------ submit.php ------

<?php header("Location: ../index.php"); ?>

Solution 9:[9]

simple just ignore the action attribute and use !empty (not empty) in php.

<form method="post">
        <input type="name" name="name">
        <input type="submit">
    </form>
    <?PHP
       if(!empty($_POST['name']))
       { 
           echo $_POST['name'];
       }
    ?>

Solution 10:[10]

I know this is an old question but since it came up as the top answer on Google, it is worth an update.

You do not need to use jQuery or JavaScript to stay on the same page after form submission.

All you need to do is get PHP to return just a status code of 204 (No Content).

That tells the page to stay where it is. Of course, you will probably then want some JavaScript to empty the selected filename.

Solution 11:[11]

What I do is I want the page to stay after submit when there are errors...So I want the page to be reloaded :

($_SERVER["PHP_SELF"])

While I include the sript from a seperate file e.g

include_once "test.php";

I also read somewhere that

if(isset($_POST['submit']))

Is a beginners old fasion way of posting a form, and

if ($_SERVER['REQUEST_METHOD'] == 'POST')

Should be used (Not my words, read it somewhere)

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