'PHP Deprecated: Automatic conversion of false to array is deprecated adodb-mssqlnative.inc.php on line 154
We are upgrading PHP to version 8.1. Using MS Sql Server DB. It all seems to work correctly but I see repeated messages in the log file:
[03-Feb-2022 11:51:18 America/New_York] PHP Deprecated: Automatic conversion of false to array is deprecated in C:...\includes\adodb\drivers\adodb-mssqlnative.inc.php on line 154
I've updated adodb to version version 5.22 but that did not stop the messges from logging. The ini file has
extension=php_sqlsrv_81_nts_x64.dll
extension=php_pdo_sqlsrv_81_nts_x64.dll
Does anyone know how to fix this problem?
Solution 1:[1]
This is a known issue of backwards incompatibility, affecting the ADOdb library version 5.22.1 and older. PHP 8.1 warns you on autovivification of false-y values and some future version of PHP will throw an error when you do it.
PHP natively allows for autovivification (auto-creation of arrays from falsey values). This feature is very useful and used in a lot of PHP projects, especially if the variable is undefined. However, there is a little oddity that allows creating an array from a false and null value.
And they give this example
// From false
$arr = false;
$arr[] = 2;
I went and found the file in question and this is the function it's in
function ServerInfo() {
global $ADODB_FETCH_MODE;
static $arr = false;
if (is_array($arr))
return $arr;
if ($this->fetchMode === false) {
$savem = $ADODB_FETCH_MODE;
$ADODB_FETCH_MODE = ADODB_FETCH_NUM;
} elseif ($this->fetchMode >=0 && $this->fetchMode <=2) {
$savem = $this->fetchMode;
} else
$savem = $this->SetFetchMode(ADODB_FETCH_NUM);
$arrServerInfo = sqlsrv_server_info($this->_connectionID);
$ADODB_FETCH_MODE = $savem;
$arr['description'] = $arrServerInfo['SQLServerName'].' connected to '.$arrServerInfo['CurrentDatabase'];
$arr['version'] = $arrServerInfo['SQLServerVersion'];//ADOConnection::_findvers($arr['description']);
return $arr;
}
The problem is that it starts with
static $arr = false;
and then tries to autovivificate a non-array (line 154 in your error)
$arr['description'] = $arrServerInfo['SQLServerName'].' connected to '.$arrServerInfo['CurrentDatabase'];
You should be able to fix it (in theory) by making sure it's an array (something they should have done anyways). Add this above that line to make it one before it tries to append
if(!is_array($arr)) $arr = [];
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 |
