Passing the path of a file as an argument in bash

Question

I have a bash script like this where I pass in a file path into it

groups=$1
file=$2

if $groups
then
    sh with_groups.sh $file
else
    sh without_groups.sh $file
fi

What I currently do: Open the folder where my file is, do pwd, copy the link, add some_csv.csv to it and run the above script. I want to find a more efficient way to do it.

The equivalent of what I would would be something like

sh ./../run_script.sh true pwd/some_csv.csv

where pwd is the current path I am in (true refers to the first argument. You can disregard that for the purpose of this question)