'Oracle - Rank and transform on columns
I got a sample data as below in this cte_orders. Each row is a order and contains the user_id, zone_code and zone_name.
I need to rank the top 3 zone_code for each user_id, and I need the output be on columns. Like this
|user_id | top1_zone | top2_zone | top3_zone |
|--------+-------------+-------------+-------------+
|1000 | 5555-ABCD | 4567-ZMNY | 7888-IXPO |
|--------+-------------+-------------+-------------+
|9999 | 3456-JJKL | 7688-HBGT | 5555-ABCD |
|--------+-------------+-------------+-------------+
Here's the SQL with the test data and the query that I'm trying. The problem with this query is the result is given a row for each position of the rank.
(
SELECT 1 as order_id, '1000' as user_id, '5555' as zone_code, 'ABCD' as zone_name from dual union all
SELECT 2 as order_id, '1000' as user_id, '4567' as zone_code, 'ZMNY' as zone_name from dual union all
SELECT 3 as order_id, '1000' as user_id, '5555' as zone_code, 'ABCD' as zone_name from dual union all
SELECT 4 as order_id, '1000' as user_id, '5555' as zone_code, 'ABCD' as zone_name from dual union all
SELECT 5 as order_id, '1000' as user_id, '5599' as zone_code, 'HZTR' as zone_name from dual union all
SELECT 6 as order_id, '1000' as user_id, '4567' as zone_code, 'ZMNY' as zone_name from dual union all
SELECT 7 as order_id, '1000' as user_id, '4567' as zone_code, 'ZMNY' as zone_name from dual union all
SELECT 8 as order_id, '1000' as user_id, '5555' as zone_code, 'ABCD' as zone_name from dual union all
SELECT 9 as order_id, '1000' as user_id, '1999' as zone_code, 'LNKJ' as zone_name from dual union all
SELECT 10 as order_id, '1000' as user_id, '5677' as zone_code, 'OPLH' as zone_name from dual union all
SELECT 11 as order_id, '1000' as user_id, '7888' as zone_code, 'IXPO' as zone_name from dual union all
SELECT 12 as order_id, '9999' as user_id, '5599' as zone_code, 'HZTR' as zone_name from dual union all
SELECT 13 as order_id, '9999' as user_id, '3456' as zone_code, 'JJKL' as zone_name from dual union all
SELECT 14 as order_id, '9999' as user_id, '5555' as zone_code, 'ABCD' as zone_name from dual union all
SELECT 15 as order_id, '9999' as user_id, '3456' as zone_code, 'JJKL' as zone_name from dual union all
SELECT 16 as order_id, '9999' as user_id, '5555' as zone_code, 'ABCD' as zone_name from dual union all
SELECT 17 as order_id, '9999' as user_id, '7688' as zone_code, 'HBGT' as zone_name from dual union all
SELECT 17 as order_id, '9999' as user_id, '7688' as zone_code, 'HBGT' as zone_name from dual union all
SELECT 18 as order_id, '9999' as user_id, '1566' as zone_code, 'LNOI' as zone_name from dual union all
SELECT 19 as order_id, '9999' as user_id, '3456' as zone_code, 'JJKL' as zone_name from dual union all
SELECT 20 as order_id, '9999' as user_id, '7654' as zone_code, 'NNJJ' as zone_name from dual union all
SELECT 21 as order_id, '9999' as user_id, '4433' as zone_code, 'NHJE' as zone_name from dual union all
SELECT 22 as order_id, '9999' as user_id, '4111' as zone_code, 'ABHJ' as zone_name from dual
)
select
user_id,
CASE WHEN rank_zones = 1 then zone_concat end as top1_zone,
CASE WHEN rank_zones = 2 then zone_concat end as top2_zone,
CASE WHEN rank_zones = 3 then zone_concat end as top3_zone
from
(
select
user_id,
zone_code||'-'||zone_name as zone_concat,
row_number() over (partition by user_id order by count(*) desc) rank_zones
from cte_orders
group by
user_id,
zone_code||'-'||zone_name
)
where rank_zones <= 3
group by
user_id,
CASE WHEN rank_zones = 1 then zone_concat end,
CASE WHEN rank_zones = 2 then zone_concat end,
CASE WHEN rank_zones = 3 then zone_concat end
order by user_id;
The output that i getting
|user_id | top1_zone | top2_zone | top3_zone |
|--------+-------------+-------------+-------------+
|1000 | 5555-ABCD | (null) | (null) |
|--------+-------------+-------------+-------------+
|1000 | (null) | 4567-ZMNY | (null) |
|--------+-------------+-------------+-------------+
|1000 | (null) | (null) | 7888-IXPO |
|--------+-------------+-------------+-------------+
|9999 | 3456-JJKL | (null) | (null) |
|--------+-------------+-------------+-------------+
|9999 | (null) | 7688-HBGT | (null) |
|--------+-------------+-------------+-------------+
|9999 | (null) | (null) | 5555-ABCD |
|--------+-------------+-------------+-------------+
How can i fix my query to get one row for each user_id without the nulls?
Solution 1:[1]
How can i fix my query to get one row for each user_id without the nulls?
With a little bit of aggregation (and comments, as its consequence).
Sample data:
SQL> with cte_orders as (
2 SELECT 1 as order_id, '1000' as user_id, '5555' as zone_code, 'ABCD' as zone_name from dual union all
3 SELECT 2 as order_id, '1000' as user_id, '4567' as zone_code, 'ZMNY' as zone_name from dual union all
4 SELECT 3 as order_id, '1000' as user_id, '5555' as zone_code, 'ABCD' as zone_name from dual union all
5 SELECT 4 as order_id, '1000' as user_id, '5555' as zone_code, 'ABCD' as zone_name from dual union all
6 SELECT 5 as order_id, '1000' as user_id, '5599' as zone_code, 'HZTR' as zone_name from dual union all
7 SELECT 6 as order_id, '1000' as user_id, '4567' as zone_code, 'ZMNY' as zone_name from dual union all
8 SELECT 7 as order_id, '1000' as user_id, '4567' as zone_code, 'ZMNY' as zone_name from dual union all
9 SELECT 8 as order_id, '1000' as user_id, '5555' as zone_code, 'ABCD' as zone_name from dual union all
10 SELECT 9 as order_id, '1000' as user_id, '1999' as zone_code, 'LNKJ' as zone_name from dual union all
11 SELECT 10 as order_id, '1000' as user_id, '5677' as zone_code, 'OPLH' as zone_name from dual union all
12 SELECT 11 as order_id, '1000' as user_id, '7888' as zone_code, 'IXPO' as zone_name from dual union all
13 SELECT 12 as order_id, '9999' as user_id, '5599' as zone_code, 'HZTR' as zone_name from dual union all
14 SELECT 13 as order_id, '9999' as user_id, '3456' as zone_code, 'JJKL' as zone_name from dual union all
15 SELECT 14 as order_id, '9999' as user_id, '5555' as zone_code, 'ABCD' as zone_name from dual union all
16 SELECT 15 as order_id, '9999' as user_id, '3456' as zone_code, 'JJKL' as zone_name from dual union all
17 SELECT 16 as order_id, '9999' as user_id, '5555' as zone_code, 'ABCD' as zone_name from dual union all
18 SELECT 17 as order_id, '9999' as user_id, '7688' as zone_code, 'HBGT' as zone_name from dual union all
19 SELECT 17 as order_id, '9999' as user_id, '7688' as zone_code, 'HBGT' as zone_name from dual union all
20 SELECT 18 as order_id, '9999' as user_id, '1566' as zone_code, 'LNOI' as zone_name from dual union all
21 SELECT 19 as order_id, '9999' as user_id, '3456' as zone_code, 'JJKL' as zone_name from dual union all
22 SELECT 20 as order_id, '9999' as user_id, '7654' as zone_code, 'NNJJ' as zone_name from dual union all
23 SELECT 21 as order_id, '9999' as user_id, '4433' as zone_code, 'NHJE' as zone_name from dual union all
24 SELECT 22 as order_id, '9999' as user_id, '4111' as zone_code, 'ABHJ' as zone_name from dual
25 )
This is what makes what you ask for (the MAX aggregate function; lines #28 - 30):
26 select
27 user_id,
28 max(CASE WHEN rank_zones = 1 then zone_concat end) as top1_zone,
29 max(CASE WHEN rank_zones = 2 then zone_concat end) as top2_zone,
30 max(CASE WHEN rank_zones = 3 then zone_concat end) as top3_zone
31 from
32 (
33 select
34 user_id,
35 zone_code||'-'||zone_name as zone_concat,
36 row_number() over (partition by user_id order by count(*) desc) rank_zones
37 from cte_orders
38 group by
39 user_id,
40 zone_code||'-'||zone_name
41 )
42 where rank_zones <= 5
Comment CASE expressions (lines #45 - 47):
43 group by
44 user_id
45 -- CASE WHEN rank_zones = 1 then zone_concat end,
46 -- CASE WHEN rank_zones = 2 then zone_concat end,
47 -- CASE WHEN rank_zones = 3 then zone_concat end
48 order by user_id;
And the result is then:
USER TOP1_ZONE TOP2_ZONE TOP3_ZONE
---- --------- --------- ---------
1000 5555-ABCD 4567-ZMNY 5599-HZTR
9999 3456-JJKL 5555-ABCD 7688-HBGT
SQL>
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Littlefoot |
