'My react onClick navigate shows URL, but does not render component
I am new to React router here and I am trying to make clicking on a recipe in my 'BrowseRecipes' page redirect to a page dedicated to that recipe. However, when I click on the recipe, the URL shows the correct URL /browse/${recipeID}, but the page I assign to this route does not render. Only the /browse page with a list of all the recipes renders. Does anyone know why?
Here is my APP.js
import AddNewRecipe from './components/AddNewRecipe'
import BrowseRecipes from './components/BrowseRecipes'
import { currentState } from './components/redux';
import ReactDOM from 'react-dom'
import { BrowserRouter as Router, Switch, Route, Routes, Link, useParams} from "react-router-dom";
import AuthReqPage from "./components/AuthReqPage"
import Navbar from "./components/Navbar"
import RecipePage from "./components/BrowseRecipes/RecipePage"
import PageNotFound from "./components/PageNotFound"
function App(props) {
return (
<Router>
<div className="App">
<Navbar />
<Routes>
<Route path='/add' element={<AddNewRecipe />} />
<Route path='/' element={<BrowseRecipes />} />
<Route path='/browse' element={<BrowseRecipes />}>
<Route path=':recipeID' element={<RecipePage />}/>
</Route>
<Route path='/authrequired' element={<AuthReqPage />} />
<Route path='/*' element={<PageNotFound />} />
</Routes>
</div>
</Router>
);
}
export default App;
Here is my BrowseRecipe component/page:
export function BrowseRecipes (props){
console.log('browseRecipe running')
let navigate = useNavigate()
let params=useParams()
console.log(params.recipeID)
if(props.recipeStore.length>0)
{
var displayRecipes = props.recipeStore.map(
elem=>
{
return (<li key={elem.recipeID} className='recipeDisplayBox' onClick={()=>navigate(`/browse/${elem.recipeID}`)}>
{elem.title},
Prep: {elem.prepTime.numeral} {elem.prepTime.unit}
</li>)
}
)
}
return(
<div>
<h1>Browse Recipes</h1>
<h2>Your recipes:</h2>
<ul>
{displayRecipes}
</ul>
</div>
)
}
const mapStateToProps=(state)=>{
return {recipeStore: state.recipe}}
export default connect(mapStateToProps)(RequireAuth(BrowseRecipes))
And here is the individual recipe page that failed to render:
export function RecipePage (props){
console.log('RecipePage running')
let params=useParams()
return(
<div>
<h1>{params.recipeID}</h1>
</div>
)
}
const mapStateToProps=(state)=>{
return {recipeStore: state.recipe}}
export default connect(mapStateToProps)(RequireAuth(RecipePage))
"RequireAuth" here is a higher-order component that redirects the page to 'Please Sign In' page if the user is not signed in.
Did I misunderstand something about the use of UseParams? Please help me shed some light! Thank you very much
Solution 1:[1]
You've rendered the RecipePage component on a nested route from the "/browse" route rendering the BrowseRecipes component.
<Route path='/browse' element={<BrowseRecipes />}>
<Route path=':recipeID' element={<RecipePage />}/>
</Route>
In this configuration the BrowseRecipes is required to render an Outlet component for the nested routes to be rendered into.
Example:
import { Outlet, useNavigate, useParams } from 'react-router-dom';
export function BrowseRecipes (props) {
const navigate = useNavigate();
const params = useParams();
let displayRecipes;
if (props.recipeStore.length) {
displayRecipes = props.recipeStore.map(elem => {
return (
<li
key={elem.recipeID}
className='recipeDisplayBox'
onClick={() => navigate(`/browse/${elem.recipeID}`)}
>
{elem.title},
Prep: {elem.prepTime.numeral} {elem.prepTime.unit}
</li>
);
});
}
return (
<div>
<h1>Browse Recipes</h1>
<h2>Your recipes:</h2>
<ul>
{displayRecipes}
</ul>
<Outlet /> // <-- nested routes render here
</div>
);
}
If you don't want to render both BrowseRecipes and RecipePage at the same time, then create a nested index route specifically for BrowseRecipes.
Example:
<Route path='/browse'>
<Route index element={<BrowseRecipes />} /> // <-- "/browse"
<Route path=':recipeID' element={<RecipePage />} /> // <-- "/browse/:recipeID"
</Route>
For more information, see:
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Drew Reese |
