my code in c++. Will there be a memory leak?

Question

int * myArr(int num) {
    static int *Arr = new int[num];
    for (int i{ 0 }; i < num; i++) {
        *(Arr + i) = i;
        std::cout << *(Arr + i) << "\n";
    }
    //delete[] Arr;
    return Arr;
}

int main()
{
    int *testArr = myArr(4);
    for (int i{ 0 }; i < 4; i++) {
        std::cout << *(testArr + i) << "\n";
    }
    delete[] testArr;
}

is there a memory leak if i try to delete[] testArr inside main() instead of delete[] Arr in the myArr function? Thanks for your reply.

Answer 1

Will there be a memory leak?

There is no leak in the example.

if i try to delete[] testArr inside main() instead of delete[] Arr in the myArr function?

If you did that, then attempting to access the array in main would result in undefined behaviour. Don't do that.

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P.S. Don't use bare owning pointers. Use std::vector instead. Example:

std::vector<int> myArr(int num) {
    auto iota = std::ranges::iota_view{0, num};
    return std::vector<int>(iota.begin(), iota.end());
}