'Moving average within groups that returns NULL if any row is NULL (Snowflake - SQL)
I need to caluclate the moving average of a column per group (partitioned by id). The only twist is that I need the result to be NULL if any value in the corresponding window is NULL.
Example of expected behaviour (for a given id and window size=3):
| A | mov_ave_A |
|---|---|
| NULL | NULL |
| 1 | NULL |
| 1 | NULL |
| 1 | 1 |
| 4 | 2 |
The first 3 rows of the moving average are NULL, because the first value (which is included in the first 3 windows) is NULL. Row 4 of mov_ave_A is equal to 1 because it's the average of rows 2 to 4 of A, and so on.
I tried:
CASE WHEN SUM(CASE WHEN a IS NULL THEN 1 ELSE 0 END) = 0 THEN AVG(a) ELSE NULL END
OVER (
PARTITION BY id
ORDER BY date_month
ROWS BETWEEN 2 PRECEDING AND CURRENT ROW) AS mov_ave_A
but I get
"Sliding window frame unsupported for function CASE".
Also, I'd really like the solution to be short and simple as I need to create 6 such columns. So, I'll have to repeat the logic 6 times.
Solution 1:[1]
The issue with your query is the OVER clause is after the END. I believe this should work. You need to have the OVER clause for each window function so once for COUNT and once for AVG. COUNT is a easier to way to check for NULL's then using SUM
SELECT
*
,CASE
/*Check for 3 values in a, if so return the rolling AVG value. Implicit ELSE NULL*/
WHEN COUNT(a) OVER (PARTITION BY ID ORDER BY date_month ROWS BETWEEN 2 PRECEDING AND CURRENT ROW) = 3
THEN AVG(a) OVER (PARTITION BY ID ORDER BY date_month ROWS BETWEEN 2 PRECEDING AND CURRENT ROW)
END AS mov_ave_A
FROM YourTable
Solution 2:[2]
Use the following case expression:
CASE WHEN COUNT(a) OVER (
PARTITION BY id
ORDER BY date_month
ROWS BETWEEN 2 PRECEDING AND CURRENT ROW
) = 3 THEN AVG(a) OVER (
PARTITION BY id
ORDER BY date_month
ROWS BETWEEN 2 PRECEDING AND CURRENT ROW
) END AS mov_avg
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | Stephan |
| Solution 2 |
