'Match first and then all equal occurrences with regex

Lets say we have the string:

one day, when Anne, Lisa and Paul went to the store, then Anne said to Paul: "I love Lisa!". Then Lisa laughed and kissed Anne.

is there a way with regex to match the first name, and then match and all other occurrences of the same name in the string?

Given the name-matching regex /[A-Z][a-z]+ (with /g maybe?), can the regex matcher be made to remember the first match, and then use that match EXACTLY for the rest of the string? Other subsequent matches to the name-matching regex should be ignored (except for Anne in the example).

The result would be (if matches are replaced with "Foo"):

one day, when Foo, Lisa and Paul went to the store, then Foo said to Paul: "I love Lisa!". Then Lisa laughed and kissed Foo.

Please ignore the fact that the sentence start uncapitalized, or add an example that also handles this.

Using a script to get the first match and then using that as input for a second iteration works of course, but that's outside the scope of the question (which is limited to ONE regex expression).

regexhtmlcontenteditablespell-checking


Solution 1:[1]

Based on the current documentation, it can be done but using help from javascript to control the output.

<html lang="id">
 <body>
  <main contentEditable="true">
   <h1 lang="id">hello apa kabar</h1>
   <h1 lang="en">Hello how are you</h1>
  </main>
 </body>
</html>

You can detect the language, then with the help from javascript to show or hide the respective div based on the detected language.

Sources

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Source: Stack Overflow

Solution Source
Solution 1 Fadli Saad

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