'L298n Convert Python code for Raspberry to Google Coral
I just want to use the code below with the Google Coral Dev board (https://coral.ai/docs/dev-board-mini/gpio/#header-pinout)
Here's where the code comes from (for raspberryPI) https://www.youtube.com/watch?v=2bganVdLg5Q
But I want to use it for Google Dev Board.
I am a beginner, so I need some help.
I think this stackoverflow answer could help:
Google EdgeTPU can't get PWM to work with Python
# Python Script
# https://www.electronicshub.org/raspberry-pi-l298n-interface-tutorial-control-dc-motor-l298n-raspberry-pi/
import RPi.GPIO as GPIO
from time import sleep
in1 = 24
in2 = 23
en = 25
temp1=1
GPIO.setmode(GPIO.BCM)
GPIO.setup(in1,GPIO.OUT)
GPIO.setup(in2,GPIO.OUT)
GPIO.setup(en,GPIO.OUT)
GPIO.output(in1,GPIO.LOW)
GPIO.output(in2,GPIO.LOW)
p=GPIO.PWM(en,1000)
p.start(25)
print("\n")
print("The default speed & direction of motor is LOW & Forward.....")
print("r-run s-stop f-forward b-backward l-low m-medium h-high e-exit")
print("\n")
while(1):
x=raw_input()
if x=='r':
print("run")
if(temp1==1):
GPIO.output(in1,GPIO.HIGH)
GPIO.output(in2,GPIO.LOW)
print("forward")
x='z'
else:
GPIO.output(in1,GPIO.LOW)
GPIO.output(in2,GPIO.HIGH)
print("backward")
x='z'
elif x=='s':
print("stop")
GPIO.output(in1,GPIO.LOW)
GPIO.output(in2,GPIO.LOW)
x='z'
elif x=='f':
print("forward")
GPIO.output(in1,GPIO.HIGH)
GPIO.output(in2,GPIO.LOW)
temp1=1
x='z'
elif x=='b':
print("backward")
GPIO.output(in1,GPIO.LOW)
GPIO.output(in2,GPIO.HIGH)
temp1=0
x='z'
elif x=='l':
print("low")
p.ChangeDutyCycle(25)
x='z'
elif x=='m':
print("medium")
p.ChangeDutyCycle(50)
x='z'
elif x=='h':
print("high")
p.ChangeDutyCycle(75)
x='z'
elif x=='e':
GPIO.cleanup()
print("GPIO Clean up")
break
else:
print("<<< wrong data >>>")
print("please enter the defined data to continue.....")
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
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