JS regular expression Allow alphanumeric characters and . , " ( ) - _ # : ; * @ & not remaining +, =, $, !, <, >, `, ~, {, }, |,\,?, ~

Question

i tried with below pattern

var pattern = new RegExp("^[ A-Za-z0-9.,()-_#:;*@&]*$");
console.log(pattern.test("asda ?"));// giving true

but with, i need to get the false. Please provides regExp to allow alphanumeric characters and . , " ( ) - _ # : ; * @ & not remaining special chars +, =, $, !, <, >, `, ~, {, }, |,?, ~

Answer 1

You could try this:

var pattern = new RegExp(/"^[ A-Za-z0-9.,()-_#:;*@&]*$"/);
console.log(pattern.test("asda ?"));// giving true

this should allow your variable to accept universal characters

Answer 2

A dash (-) in the middle of a character class ([...]) means interval.
A-Z means all characters between and including A and Z.
The same way, )-_ does not mean any of ), - and _ but all characters between ) and _. This range includes digits, uppercase letters and a lot of other characters you want to exclude (+, <, ,>, ? etc). Check the ASCII table to find the complete list.

In order to prevent the dash (-) to have a special meaning in a character class you can put it as the last character in the class.

Use the following fragment of code in your browser to see how the regex matches (or doesn't match) the printable ASCII characters:

let pattern = new RegExp("^[ A-Za-z0-9.,()_#:;*@&-]*$");

for (let i = ' '.charCodeAt(0); i < '~'.charCodeAt(0); i ++) {
  console.log(`'${String.fromCharCode(i)}': ${pattern.test(String.fromCharCode(i))}`);
}