'jQuery - Illegal invocation

jQuery v1.7.2

I have this funcion that is giving me the following error while executing :

Uncaught TypeError: Illegal invocation

Here's the function :

$('form[name="twp-tool-distance-form"]').on('submit', function(e) {
    e.preventDefault();

    var from = $('form[name="twp-tool-distance-form"] input[name="from"]');
    var to = $('form[name="twp-tool-distance-form"] input[name="to"]');
    var unit = $('form[name="twp-tool-distance-form"] input[name="unit"]');
    var speed = game.unit.speed($(unit).val());

    if (!/^\d{3}\|\d{3}$/.test($(from).val()))
    {
        $(from).css('border-color', 'red');
        return false;
    }

    if (!/^\d{3}\|\d{3}$/.test($(to).val()))
    {
        $(to).css('border-color', 'red');
        return false;
    }

    var data = {
        from : from,
        to : to,
        speed : speed
    };

    $.ajax({
        url : base_url+'index.php',
        type: 'POST',
        dataType: 'json',
        data: data,
        cache : false
    }).done(function(response) {
        alert(response);
    });

    return false;
});

If I remove data from ajax call, it works .. any suggestions?

Thanks!



Solution 1:[1]

Try to set processData: false in ajax settings like this

$.ajax({
    url : base_url+'index.php',
    type: 'POST',
    dataType: 'json',
    data: data,
    cache : false,
    processData: false
}).done(function(response) {
    alert(response);
});

Solution 2:[2]

Just for the record it can also happen if you try to use undeclared variable in data like

var layout = {};
$.ajax({
  ...
  data: {
    layout: laoyut // notice misspelled variable name
  },
  ...
});

Solution 3:[3]

If you want to submit a form using Javascript FormData API with uploading files you need to set below two options:

processData: false,
contentType: false

You can try as follows:

//Ajax Form Submission
$(document).on("click", ".afs", function (e) {
    e.preventDefault();
    e.stopPropagation();
    var thisBtn = $(this);
    var thisForm = thisBtn.closest("form");
    var formData = new FormData(thisForm[0]);
    //var formData = thisForm.serializeArray();

    $.ajax({
        type: "POST",
        url: "<?=base_url();?>assignment/createAssignment",
        data: formData,
        processData: false,
        contentType: false,
        success:function(data){
            if(data=='yes')
            {
                alert('Success! Record inserted successfully');
            }
            else if(data=='no')
            {
                alert('Error! Record not inserted successfully')
            }
            else
            {
                alert('Error! Try again');
            }
        }
    });
});

Solution 4:[4]

In my case, I just changed

Note: This is in case of Django, so I added csrftoken. In your case, you may not need it.

Added contentType: false, processData: false

Commented out "Content-Type": "application/json"

$.ajax({
    url: location.pathname, 
    type: "POST",
    crossDomain: true,
    dataType: "json",
    headers: {
        "X-CSRFToken": csrftoken,
        "Content-Type": "application/json"
    },
    data:formData,
    success: (response, textStatus, jQxhr) => {

    },
    error: (jQxhr, textStatus, errorThrown) => {

    }
})

to

$.ajax({
    url: location.pathname, 
    type: "POST",
    crossDomain: true,
    dataType: "json",
    contentType: false,
    processData: false,
    headers: {
        "X-CSRFToken": csrftoken
        // "Content-Type": "application/json",
    },
    data:formData,
    success: (response, textStatus, jQxhr) => {

    },
    error: (jQxhr, textStatus, errorThrown) => {

    }
})

and it worked.

Solution 5:[5]

In My case I have't define all variables which I am passing to data in ajax.

var page = 1;

$.ajax({
    url: 'your_url',
    type: "post",
    data: { 'page' : page, 'search_candidate' : search_candidate }
    success: function(result){
        alert('function called');
    }
)}

I have just defined variable var search_candidate = "candidate name"; and its working.

var page = 1;
var search_candidate = "candidate name"; // defined
$.ajax({
    url: 'your_url',
    type: "post",
    data: { 'page' : page, 'search_candidate' : search_candidate }
    success: function(result){
        alert('function called');
    }
)}

Solution 6:[6]

My problem was unrelated to processData. It was because I sent a function that cannot be called later with apply because it did not have enough arguments. Specifically I shouldn't have used alert as the error callback.

$.ajax({
    url: csvApi,
    success: parseCsvs,
    dataType: "json",
    timeout: 5000,
    processData: false,
    error: alert
});

See this answer for more information on why that can be a problem: Why are certain function calls termed "illegal invocations" in JavaScript?

The way I was able to discover this was by adding a console.log(list[ firingIndex ]) to jQuery so I could track what it was firing.

This was the fix:

function myError(jqx, textStatus, errStr) {
    alert(errStr);
}

$.ajax({
    url: csvApi,
    success: parseCsvs,
    dataType: "json",
    timeout: 5000,
    error: myError // Note that passing `alert` instead can cause a "jquery.js:3189 Uncaught TypeError: Illegal invocation" sometimes
});

Solution 7:[7]

In my case (using webpack 4) within an anonymous function, that I was using as a callback.

I had to use window.$.ajax() instead of $.ajax() despite having:

import $ from 'jquery';
window.$ = window.jQuery = $;

Solution 8:[8]

Also this is a cause too: If you built a jQuery collection (via .map() or something similar) then you shouldn't use this collection in .ajax()'s data. Because it's still a jQuery object, not plain JavaScript Array. You should use .get() at the and to get plain js array and should use it on the data setting on .ajax().

Solution 9:[9]

Working for me. processData: false, contentType: false, is required for working.

 var formData = new FormData($('#author_post')[0]);
 formData.append('t','author-add');
 $.ajax({
        type: 'POST',
        url: 'url-here',
        cache: false,
        processData: false,
        contentType: false,
        data:formData,
        success: function(response) {
           //success code
        }
 });

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1 Justo
Solution 2 Ivan Ivanic
Solution 3
Solution 4
Solution 5 Rajesh Kharatmol
Solution 6 Community
Solution 7 zanderwar
Solution 8 Burak TARHANLI
Solution 9 Rana Nadeem