'Javascript while with time delay
My goal I want to run loop that decrements a global variable stepwise in n ms (for Example: 200ms) time intervals.
Thanks in advance!
What i already tried
I tried to use ascy await. But in combination with css transition i run in an infinite loop (In codepen.io). But here in SO you will see that it starts not running smoothly if you keep pressing arrow up.
const procentage = document.querySelector(".procentage");
const green = engine.querySelector(".green");
let number = 0;
let decrementing = false;
window.addEventListener('keydown', (e) => {
e = e || window.event;
e.preventDefault();
if (e.keyCode == '38') {
console.log("accelerate");
actionHandler( number++ );
decrementing = false;
downLoop();
}
});
function actionHandler(num) {
procentage.innerHTML = num;
const str = num + "%"
green.style.width = str;
procentage.innerHTML = str;
}
window.addEventListener('keyup', (e) => {
e = e || window.event;
e.preventDefault();
if (e.keyCode == '38') {
console.log("decelerate");
decrementing = true;
downLoop();
}
});
async function downLoop() {
if (! decrementing) {
return false
};
const timer = ms => new Promise(res => setTimeout(res, ms));
while (number > 1) {
// how to decrement ever 200ms???
actionHandler( number-- );
await timer(200)
}
}
#engine {
background-color:black;
height: 50px;
position: relative;
}
p {
text-align: center;
}
.green {
background:green;
height: 50px;
width:0%;
transition: width 0.2s;
text-align:center;
}
.procentage {
position:absolute;
top: 50%;
left: 50%;
transform: translate(0%,-50%);
color: white;
fon-weight: bold;
font-size:28px;
}
<div id="engine">
<div><span class="procentage">0</span></div>
<div class="green"></div>
</div>
<p>press arrow Up</p>
Solution 1:[1]
From the above comments ...
"Instead of incrementing each time the
numbervalue push a new async timer function, set to 200 msec delay but not immediately triggered, into an array. Create an async generator from it and iterate over the latter via thefor-await...ofstatement where one could decrementnumberagain." – Peter Seliger"@PeterSeliger Hi Peter! Thank you for your comment. Can you make a small example please?" – Maik Lowrey
And here the requested demonstration.
function createWait(delay) {
return async function wait () {
let settle;
const promise = new Promise((resolve) => { settle = resolve;});
setTimeout(settle, delay, { delay, state: 'ok' });
return promise;
};
}
async function* getWaitIterables(list) {
let wait;
while (wait = list.shift()) {
yield wait();
}
}
// demo for ...
// - creating an async `wait` function
// or a list of such kind.
// - creating an async generator from
// a list of async `wait` functions.
// - iterating an async generator of
// async `wait` functions.
const waitingList = [ // const waitingList = [];
2000, // waitingList.push(createWait(2000));
1000, // waitingList.push(createWait(1000));
3000, // waitingList.push(createWait(3000));
].map(createWait); // - The OP of cause needs to push into.
let number = 3; // - The incremented `number` value e.g. ... 3.
(async () => {
for await (const { delay, state } of getWaitIterables(waitingList)) {
--number;
console.log({ number, delay, state });
}
})();
console.log('... running ...', { number });
.as-console-wrapper { min-height: 100%!important; top: 0; }
Solution 2:[2]
You can do this:
Expression<Func<A, bool>> predicate1 = x=> x.f1 == val1;
Expression<Func<A, bool>> predicate2 = x=> x.f2 == val2;
Expression<Func<A, bool>> predicate3 = x=> x.f3 == val3;
Expression<Func<A, bool>> predicate4 = x=> x.f4 == val4;
var body = Expression.Or(predicate1.Body, predicate2.Body);
var lambda = Expression.Lambda<Func<A, bool>>(body, predicate2.Parameters[0]);
body = Expression.Or(lambda.Body, predicate3.Body);
lambda = Expression.Lambda<Func<A, bool>>(body, predicate3.Parameters[0]);
body = Expression.Or(lambda.Body, predicate4.Body);
var finalExpression = Expression.Lambda<Func<A, bool>>(body, predicate4.Parameters[0]);
You can pass finalExpression to the filter.
If you want to use And instead of Or, Just replace Or method with And
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | |
| Solution 2 |
