'Javascript match function for special characters

I am working on this code and using "match" function to detect strength of password. how can I detect if string has special characters in it?

if(password.match(/[a-z]+/)) score++;
if(password.match(/[A-Z]+/)) score++;
if(password.match(/[0-9]+/)) score++;

Solution 1:^[1]

If you mean !@#$% and ë as special character you can use:

/[^a-zA-Z ]+/

The ^ means if it is not something like a-z or A-Z or a space.

And if you mean only things like !@$&$ use:

/\W+/

\w matches word characters, \W matching not word characters.

Solution 2:^[2]

You'll have to whitelist them individually, like so:

if(password.match(/[`~!@#\$%\^&\*\(\)\-=_+\\\[\]{}/\?,\.\<\> ...

and so on. Note that you'll have to escape regex control characters with a \.

While less elegant than /[^A-Za-z0-9]+/, this will avoid internationalization issues (e.g., will not automatically whitelist Far Eastern Language characters such as Chinese or Japanese).

Solution 3:^[3]

you can always negate the character class:

if(password.match(/[^a-z\d]+/i)) {
    // password contains characters that are *not*
    // a-z, A-Z or 0-9
}

However, I'd suggest using a ready-made script. With the code above, you could just type a bunch of spaces, and get a better score.

Solution 4:^[4]

Just do what you did above, but create a group for !@#$%^&*() etc. Just be sure to escape characters that have meaning in regex, like ^ and ( etc....

EDIT -- I just found this which lists characters that have meaning in regex.

Solution 5:^[5]

if(password.match(/[^\w\s]/)) score++;

This will match anything that is not alphanumeric or blank space. If whitespaces should match too, just use /[^\w]/.

Solution 6:^[6]

As it look from your regex, you are calling everything except for alphanumeric a special character. If that is the case, simply do.

if(password.match(/[\W]/)) {
    // Contains special character.
}

Anyhow how why don't you combine those three regex into one.

if(password.match(/[\w]+/gi)) {
    // Do your stuff.
}

Solution 7:^[7]

/[^a-zA-Z0-9 ]+/ This will accept only special characters and will not accept a to z & A to Z 0 to 9 digits

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution	Source
Solution 1	Wouter J
Solution 2
Solution 3	Flambino
Solution 4	hvgotcodes
Solution 5	mgibsonbr
Solution 6	karora
Solution 7	QUTBUDDIN KHAN

'Javascript match function for special characters

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