Is there any other way to swap address of pointers to interchange value? [closed]

Question

Is there any other way to swap address of pointers to interchange value ?

Below is one way to do the same. Here we are not changing values saved on address.

void Change_Address( int *&p, int *&pt)
{
 int *pp;
 pp = p;
 p = pt;
 pt= pp;
}
int main(void)
{
   int a =3, b = 4, *p, *p1;
   p = &a; p1 = &b;    
   printf("Values Before interchange %d %d\n", *p, *p1);
   Change_Address(p, p1);
   printf("Values after interchange %d %d", *p, *p1);    
  getch();     
  return 0;
}

Answer 1

Your code uses references which are C++, in C you would have to use pointer to pointer :

void Change_Address( int **p, int **pt)
{
 int *pp;
 pp = *p;
 *p = *pt;
 *pt= pp;
}

int main(void)
{
   int a =3, b = 4, *p, *p1;
   p = &a; p1 = &b;    
   printf("Values Before interchange %d %d\n", *p, *p1);
   Change_Address(&p, &p1);
   printf("Values after interchange %d %d", *p, *p1);    
   getch();     
   return 0;
}