'Is there a way of comparing 2 variables in a grid like way instead of nested if statements?

I am dealing with a prisoners paradox type problem where there are multiple combinations (2x2 -> 4) and each has a different result. Is there a good way of looking at the inputs and deciding the output other than nested if statements which can get confusing if theres more than 2 options for inputs. For example there are 2 prisoners being questioned: A and B. If both choose to expose the other then they both are imprisoned for 5 years, if both stay loyal then they both only recieve 1 year in prison, however if A exposes B but B remains loyal, A will be set free and B will be imprisoned for 10 years. Currently my logic looks roughly like this:

if (A.Cooperate)
{
    if (B.Cooperate)
    {
        A.Sentence = 5;
        B.Sentence = 5;
    }
    else
    {
        A.Sentence = 0;
        B.Sentence = 10;
    }
}
else
{
    if (B.Cooperate)
    {
        A.Sentence = 10;
        B.Sentence = 0;

    }
    else
    {
        A.Sentence = 1;
        B.Sentence = 1;

    }
}

Although I would like to add more options than just a boolean yes/no and fear it will become over complicated with many nested if statements.

c++sharp


Solution 1:[1]

This is how I would do it to improve readability and logic

    static void Interrogate(Prisoner A, Prisoner B)
    {
        if (!B.Cooperate && !A.Cooperate)
        {
            A.Sentence = 1;
            B.Sentence = 1;
        }
        else if (B.Cooperate && !A.Cooperate)
        {
            A.Sentence = 10;
            B.Sentence = 0;
        }
        else if (A.Cooperate && !B.Cooperate)
        {
            A.Sentence = 0;
            B.Sentence = 10;
        }
        else
        {
            A.Sentence = 5;
            B.Sentence = 5;
        }
    }

Solution 2:[2]

You can use the new switch format

       switch (A.Cooperate, B.Cooperate) {
            case (true, false): {
                .....
                }
                break;

            case (true, true): {
                ....
                }
        }

Sources

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Source: Stack Overflow

Solution Source
Solution 1
Solution 2 pm100

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