intercept all stdout, stderr and return code of all commands call in a bash script

Question

I have a brunch of bash scripts. I need to capture the stdout, stderr and return code of individual command call separately inside each bash script.

e.g.

#!/usr/bin/bash
wget https://xyz/1.tar.gz
wget https://abc/2.tar.gz

I want to get the stdout, stderr and error code of the lines wget https://xyz/1.tar.gz and wget https://abc/2.tar.gz separately and analyse the outputs.

I have too many script that I can't edit them one by one. Is there any runner or tool that I can do simple call to the high level script like:

run_and_capture_and_analyse.sh myscript.sh

I've came across the DEBUG trap approach. But the problem is that I still need to edit each script add the trap. Also, there is no way to really capture the outputs.

Thank you

EDITED: In an ideal situation, I want the outputs (stdout, stderr, return code) to be logged in different file/pipe. I only care external commands, so native controls like echo are not required. Pipe outputs should be captured just like other outputs.