'In GDB, how to print the content of a symbol which has special characters?
I encounter a small problem when debugging with GDB. The problem is like this:
When I want to get the address of 'main', I can do
gdb-peda$ p main
$1 = {<text variable, no debug info>} 0x400b21 <main>
gdb-peda$ x main
0x400b21 <main>: 0x000000b8e5894855
But if I want to get the address of '[email protected]', it becomes
gdb-peda$ x [email protected]
No symbol table is loaded. Use the "file" command.
gdb-peda$ p [email protected]
No symbol table is loaded. Use the "file" command.
And '[email protected]' actually exists.
gdb-peda$ x 0x602020
0x602020 <[email protected]>: 0x00000000004006e6
I think I have to escape '@' and '.' such that the information of '[email protected]' can be printed out successfully, but I don't know how to do. Can anyone help me?
------ 2020/05/03 edited ------
Thank @JohnKoch, I tried x &'[email protected]', it works.
Although I can't figure out why it does not just print the content of '[email protected]' when using x '[email protected]', such that I need to add &......
gdb-peda$ x/4gx '[email protected]'
0x7ffff7a649c0 <_IO_puts>: 0x55fc894954415541 0x072ee808ec834853
0x7ffff7a649d0 <_IO_puts+16>: 0x36be6f2d8b48fffa 0x4800458bc3894800
Add &:
gdb-peda$ x/4gx &'[email protected]'
0x602020 <[email protected]>: 0x00007ffff7a649c0 0x00000000004006f6
0x602030 <[email protected]>: 0x0000000000400706 0x0000000000400716
Solution 1:[1]
Use single quotes like this:
(gdb) p 'my weird symbol'
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | andrewrk |