'I am facing issue while executing JSONRenderer.render(serialized_student_data.data) in Django
I am new to Django, Whenever i execute the line json_data = JSONRenderer.render(serialized_student_data.data) it gives me error like TypeError: render() missing 1 required positional argument: 'data'
#Here is code in the models.py
class StudentModel(models.Model):
name = models.CharField(max_length=100, default='user')
roll_no = models.IntegerField(default=1)
city = models.CharField(max_length=100, default='Ahmedabad')
#Here is code in the serializers.py
class StudentSerializer(serializers.Serializer):
name = serializers.CharField(max_length=100)
roll_no = serializers.IntegerField()
city = serializers.CharField(max_length=100)
#Here is code in the views.py
def student_view(request):
student_object = StudentModel.objects.get(id=3)
serialized_student_data = StudentSerializer(student_object)
json_data = JSONRenderer.render(serialized_student_data.data)
return HttpResponse(json_data, content_type='application/json')
Solution 1:[1]
You should create JSONRender object instead of use class, and the code will be,
json_data = JSONRenderer().render(data=serialized_student_data.data)
Sources
This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.
Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 | NANDHA KUMAR |
