HTML - Flask - open a new page on button click without using Javascript

Question

I have a table with a feature to select value of a row to send it to the Flask backend, that on button click also redirects my users to a different endpoint. What I need is to open the new endpoint requested in a new webpage instead of the same page. My HTML code where the button is located is as follows. It envelopes a table column value.

{% for item in rows %}
<tr>
   <td>{{ item[0] }}</td>
   <td>
      **<button** formaction="/stockpopup" 
         type="submit" name = 'stock' value =  {{`item[11] }}>
      {{ item[11] }}**</button>**
   </td>
   <td>{{ item[1] }}</td>
</tr>
{% endfor %}
</tbody>
</table>

I am looking for possible alternates to using JavaScript to achieve this outcome if anyone can help.

Answer 1

You can use the onclick method inside of html. Something like this should work:

<button onclick="window.open('https://stackoverflow.com','_blank')">Open in new tab</button>

Answer 2

In your code you are assigning the return value of the print command to com

com = print(handsigns[0])

print in this case returns 'None', so that's what com will get assigned.

Try to print the value of com as a debugging step to see the value.

Additionally, handsigns is a list of the 3 display variables you defined above.

handsigns = [rock, paper, scissors]

Your if statement will never really work out. 'com' will end up being one of the the big docstring values you defined, not the string 'rock'

if com == 'rock':

Consider using one variable set for logic, and one for display:

choices = ["rock", "paper", "scissors"]

# get user choice, display a hand symbol for it.

com = random.choice(choices))

# have computer's choice display a hand symbol for it.

# compare user choice and com choice for message about win lose draw.