'how transform center map in address flutter

I use this code to generate the map. I would need, however, that when the user moves the map he gives me the coordinates of the center. I would then have to transform the coordinates into the street. can anyone help me?

                                      FlutterMap(
                                        mapController: _mapController,
                                        options: MapOptions(
                                          center: coordinates,
                                          minZoom: 6.132941532936457,
                                          maxZoom: 18.499999,
                                        ),
                                        layers: [
                                          TileLayerOptions(
                                            urlTemplate:'',
                                            additionalOptions: {
                                              'accessToken':
                                                  _mapboxKey.value!,
                                              'id':
                                                  'mapbox.mapbox-streets-v7',
                                            },
                                          ),
                                        ],
                                      ),


Solution 1:[1]

To achieve this you can use geolocator

This is the link for this package https://pub.dev/packages/geolocator

It will give

1 Get the last known location 2 Get the current location of the device 3 Get continuous location updates 4 Check if location services are enabled on the device 5 Calculate the distance (in meters) between two geocoordinates 6 Calculate the bearing between two geocoordinates

and using geocode package

this is the link https://pub.dev/packages/geocode

Package to make Geocode requests. It exposes two methods to translate coordinates into locations and addresses into coordinates.

using coordinates you can use maps

Sources

This article follows the attribution requirements of Stack Overflow and is licensed under CC BY-SA 3.0.

Source: Stack Overflow

Solution Source
Solution 1 Jinto Joseph