'How to view the literal content of a ZSH string containing colour codes

I'm assuming it's some sort of flag to typeset but I can't for the life of me figure it out.

zsh

Solution 1:^[1]

If you know you have valid ANSI color codes and want to get rid of them, this regex will do the trick: \x1b\[[0-?]*[ -/]*m.

With set -o extendedglob:

print -r "${variable//$'\e'\[[0-?]#[ -\/]#m/}"

Perl oneliner:

perl -pe 's/\x1b\[[0-?]*[ -\/]*m//g'

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Solution	Source
Solution 1	yut23