'How to use Zip operator of kotlin flow in Android
In my application I want combine two deferent API with ZIP operator of Kotlin flow.!
Api 1 is Movies list and Api 2 is genres list!
I want loaded each 2 Apis in one time, for this I used zip operator!
My work is true? Can I combine 2 deferent Apis with them?
ApiServices :
interface ApiServices {
@GET("movies")
suspend fun moviesList(): Response<MoviesList>
@GET("genres")
suspend fun genresList(): Response<GenresList>
}
Repository class:
class Repository @Inject constructor(private val api: ApiServices) {
suspend fun moviesList(): Flow<Response<MovieList>> {
return flow {
emit(api.moviesList(1))
}
}
suspend fun genresList(): Flow<Response<GenresList>> {
return flow {
emit(api.genresList())
}
}
}
I know show error for add deferent model class in moviesList !
But I want know how can I use Zip operator for combine 2 deferent Apis?
Solution 1:[1]
You could use combine(flow1,flow2) method to combine the flow and zipping your api response using zip , for example :
class ViewModel @Inject constructor(private val repository: Repository) : ViewModel() {
val moviesFlow = repository.moviesList()
val genresFlow = repository.genresList()
fun loadMoviesAndGenres() : Flow<List<Pair<Type1,Type2>>> = combine(moviesFlow, genresFlow) { movieList: Response<MovieList>, genreList:Response<GenresList> ->
val movies = movies.body()?.data
val genres = genres.body()
return@combine movies?.zip(genres)
}
}
How to use zip :
val listMovieTittle = listOf("avanger", "conjuring", "other")
val listGenre = listOf("action", "horror", "fantasy", "thriller")
val result1 : List<Pair<String,String>> = listMovieTittle .zip(listGenre)
println(result1 ) // [(avanger, action), (bconjuring, horror), (other, fantasy)]
val result2 : List<String> = listMovieTittle .zip(listGenre) { a, b -> "$a + $b" }
println(result2) // [avanger + action, conjuring + horror, other + fantasy]
Sources
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Source: Stack Overflow
| Solution | Source |
|---|---|
| Solution 1 |
