How to use querySelectorAll only for elements that have a specific attribute set?

Question

I'm trying to use document.querySelectorAll for all checkboxes that have the value attribute set.

There are other checkboxes on the page that do not have value set, and the value is different for each checkbox. The ids and names are not unique though.

Example: <input type="checkbox" id="c2" name="c2" value="DE039230952"/>

How do I select just those checkboxes that have values set?

Answer 1

With your example:

<input type="checkbox" id="c2" name="c2" value="DE039230952"/>

Replace $$ with document.querySelectorAll in the examples:

$$('input') //Every input
$$('[id]') //Every element with id
$$('[id="c2"]') //Every element with id="c2"
$$('input,[id]') //Every input + every element with id
$$('input[id]') //Every input including id
$$('input[id="c2"]') //Every input including id="c2"
$$('input#c2') //Every input including id="c2" (same as above)
$$('input#c2[value="DE039230952"]') //Every input including id="c2" and value="DE039230952"
$$('input#c2[value^="DE039"]') //Every input including id="c2" and value has content starting with DE039
$$('input#c2[value$="0952"]') //Every input including id="c2" and value has content ending with 0952
$$('input#c2[value*="39230"]') //Every input including id="c2" and value has content including 39230

Use the examples above directly, without the need for additional library, just by adding:

const $$ = document.querySelectorAll.bind(document);

Some additions:

$$(.) //The same as $([class])
$$(div > input) //div is parent tag to input
document.querySelector() //equals to $$()[0] or $()

Answer 2

Extra Tips:

Multiple "nots", input that is NOT hidden and NOT disabled:

:not([type="hidden"]):not([disabled])

Also did you know you can do this:

node.parentNode.querySelectorAll('div');

This is equivelent to jQuery's:

$(node).parent().find('div');

Which will effectively find all divs in "node" and below recursively, HOT DAMN!