how to transfer arrov function syntax to regular syntax, without any shorthands

Question

I am new to programming

let options = [ { type: 'vegetable', name: 'carrot', calory: 41 }, { type: 'food', name: '1 baked-egg', calory: 250 } //this below line of code is working const highCalory = options.filter(n => n.calory > 190)

problem is, I cannot translate the above arrow function syntax to regular syntax by trying below code:

const highCaloryB = options.filter(function (getCalory) { if (options['calory'] > 180) { return ${getCalory.calory} } })